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(#M40031774) ELITMUS Numerical Ability question hul Keep an EYE

Q. Number of numbers which have prime number of factorials in between 1 to 100 (hint no. of prime no. = 25)

Asked In Elitmus rohitashwa (10 years ago)

Unsolved Read Solution (14)

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Read Solution (14) :

Priyanka Pandey  (10 years ago)

ans will be 25...
2!=2*1 ... prime no of fac(2)
3!=3*2*1 ... prime no of fac(3)
4!=4*3*2*1 ... not prime no of fac
5!= 5*4*3*2*1 ... prime no of fac(5)

so on... till 100
so only prime no's have prime no of factorial and since we have 25 prime no's between 1 and 100 so ans will be 25

Is this solution Helpfull? Yes (8) | No (4)  

ashes  (10 years ago)

i think 32 is the answer
25 prime numbers + 7(2^2,2^4,2^6,3^2,3^4,5^2,7^2)

do tell me if i'm wrong

Is this solution Helpfull? Yes (7) | No (1)  

Umesh Yadav  (10 years ago)

Only number 2 is possible whose factorial is prime
Therefore Ans=1

Is this solution Helpfull? Yes (1) | No (2)  

rohitashwa  (10 years ago)

@priyanka90=2*3*3*5*1 and have prime no. of factorials

Is this solution Helpfull? Yes (1) | No (2)  

Shubham Saxena  (10 years ago)

@rohit priyanka is right and i right the same thing above.
and you are just unable to understand the question.

Is this solution Helpfull? Yes (1) | No (5)  

rohitashwa  (10 years ago)

actually it is prime no of factors..

Is this solution Helpfull? Yes (1) | No (1)  

rohitashwa  (10 years ago)

actually prime no. factors question was like so....

Is this solution Helpfull? Yes (1) | No (1)  

M.Lakshmi Durga  (10 years ago)

116 prime no of factorials

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prabhakar kumar  (10 years ago)

could u explain it

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Shubham Saxena  (10 years ago)

prime number of factorial = 2,3,5,etc number of factorial = eg:-2*1 , 3*2*1 , 5*4*3*2*1*
therefore there are 25 number of numbers which have prime number of factorials in between 1 to 100

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rohitashwa  (10 years ago)

25 prime nos have prime no of solution i.e=25+........

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will  (9 years ago)

answr should b 29
25 prime numbers which hv only 2 (prime number) factors and also the square of 2,3,5,7
total=25+4=29
all other number hav even number of factors

Is this solution Helpfull? Yes | No (1)  

aishwarya  (6 years ago)

25 prime number+10(2^2+2^3+2^4+2^5+2^6+3^2+3^3+3^4+5^2+7^2)=35

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dushyant kumar  (6 years ago)

Ans is 2.
no of nos so we have 25 prime upto 100
so ,2!=2
3!=6
5!=120 (greater than 100)
so only 2 no. those are 2, and 6 who have prime as a factorial
hope u understand

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