Latest IBPS Aptitude Question SOLUTION: an employee may claim rs 7.00 for each km when he travels by taxi and rs 6.00 for each km if he drives his own car .if in one week he claimed rs 595 for travelling km.how many kms

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(#M40031863) IBPS Numerical Ability question reasoning Keep an EYE

an employee may claim rs 7.00 for each km when he travels by taxi and rs 6.00 for each km if he drives his own car .if in one week he claimed rs 595 for travelling km.how many kms did he travel by taxi ?

Asked In IBPS ranjith (11 years ago)

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Vijay Chauhan  (11 years ago)

this question have so many solutions....
because you didn't mention min or max...rs...for the week...
595/7 = 85...so answer should be 85...
other solutions are...
let me tell one thing 7 and 6 are co-prime...so 7*6 =42...
every time reduce 42 from 595 and get new solution up to >=0...
for example...
595-42 = 553 .... 553/7 =79 by taxi and 42/6 = 7 by own car...
553-42 = 511 .... 511/7 =73 by taxi and 84/6 = 14 by own car....
like that....

Is this solution Helpfull? Yes (7) | No (1)  

mohan lal garg  (11 years ago)

travel by taxi =x km
drives his own car=y km
now according to question
7x+6y=595------------(1)
no other condition given so we can set any value of x and get y
ex-x=85 and y=0
x=79 and y=7
x=73 and y=14
x=67 and y =21
x=61 and y=28
x=55 and y=35.....
so it hv many solution...

Is this solution Helpfull? Yes (6) | No (1)  

SHUBHAM KUMAR  (10 years ago)

85 km traveled bytaxi

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vipul  (10 years ago)

solve such questions with options(hit & trial method0)

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Mani kandan  (10 years ago)

i think ans is 55

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reshma shivaji patil  (7 years ago)

Let x and y be the respective km's travelled by man via taxi and by his own car.
Given x + y = 90 => x = 90 - y
But according to the question,
7x + 6y = 595
7(90-y) + 6y = 595
=> 630 - 7y + 6y = 595
=> y = 630 - 595 = 35
=> x = 90 - 35 = 55
Therefore, the distance travelled by taxi is 55 kms.

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