Latest TCS Aptitude Question SOLUTION: A cistern is two-third full of water. Pipe A can fill the remaining part in 12 minutes and pipe B in 8 minutes. Once the cistern is emptied, how much time will these two pipes take

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(#M40003210) TCS question water Keep an EYE

A cistern is two-third full of water. Pipe A can fill the remaining part in 12 minutes and pipe B in 8 minutes. Once the cistern is emptied, how much time will these two pipes take to fill it together completely.

Asked In TCS sunil singh (13 years ago)

Solved CHANDAN KR SINGH Read Solution (2)

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CHANDAN KR SINGH  (13 years ago)

ANSWER : 14.4 min OR 14 min 24 sec.

SOLUTION :

Empty part of cistern = 1-2/3 = 1/3

A can fill in 1 min = 1/(3*12) = 1/36
B can fill in 1 min = 1/(3*8) = 1/24
Both A & B togher fill in 1 min = 1/36 + 1/24 = 5/72
So, Whole cistern can fill by both in 72/5 = 14.4 min OR 14 min 24 sec.

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Reck  (12 years ago)

A takes 12 min to fill 1/3 part
so, to fill complete part A takes 36min
similarly b takes 24 min
if they work together 1/36+1/24=5/72
they required=72/5min=14.40min

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