Latest Infosys Aptitude Question SOLUTION: EVER+SINCE=DARWIN then D+A+R+W+I+N=?

1. As it's a sum of 3 numbers hence the maximum value of D could be 2 or 1, but then we look at S which could have maximum value 9 and if it gets a carry of 1 then the value of A will be 0 and the D=1.
2. Then we looks at E and I which results in R, as 9 is already occupied by S so E could be 8 and I could be 7 and R will be 5 with carry 1.
3. Then we place the values of R=5 and E=8 resulting in N=3 with carry 1.
4. In ten's digits - E=8 and and value of C could be 3,4,6 (As all others are occupied) and To make I=7 (previously assigned in step 2) E must be added by 9 which is already occupied by S. So this hit ends here.
Now start again with reduced value of E or I, repeat above steps until you get a correct answer or a dead end.
5. Repeating above steps one time comes with E=5 and I=7 which results in R=3 carry=1.
6. Placing R=3 and E=5 in unit digits and their sum gives 8.
7. in ten's digits place E=5 now you can add 2 to make I=7 hence C=2.
8. in 100's digits you have N=8 (from step 6) and only digits that are left now are 4 and
6 hence. So placing V=4 you will get W=2 which is not true because it is already assigned to C. So we are left with only V=6 as the ultimate choice and this leads the result in to W=4.

Hence this way we got the answer

....5 6 5 3
....E V E R
..9 7 8 2 5
+ S I N C E
----------------------
D A R W I N
1 0 3 4 7 8

Hence D+A+R+W+I+N = 1+0+3+4+7+8 =23

......5 6 5 3
......E V E R
...9 7 8 2 5
+ S I N C E
----------------------
D A R W I N
1 0 3 4 7 8

Hence D+A+R+W+I+N = 1+0+3+4+7+8 =23

sir plz explain how the numbers 5653 for EVER and 97825 for SINCE came..

@VAMSI KRISHNA, SRIGAYATRI KANDUKURI, SUVARCHALA
just do one thing
give a to z values of 1-0 i.e 1,2,3,4....7,8,9,0

like:
1 2 3 4 5 6 7 8 9 0
a b c d e f g h i j k
L m n o p q r s t u v
w x y z

by this u can see that
E=5, V=2, E=5, R=8
S=9, I=9, N=4, C=3, E=5

5 2 5 8
+9 9 4 3 5
---------------
1 0 4 6 9 3
D A R W I N

D+A+R+W+I+N=1+0+4+6+9+3=23 ANS

How u guys are alloting numbers to those alphabets??? Plz explain...

plz explain

please explain

9 6 2 7 8
S I N C E
8 3 8 4
E V E R
..........
DA R W I N
10 4 5 6 2
= 18

plz explain

EVER=7458,SINCE=200235,DARWIN=207693.ANS-27

E(8)+V(7)+E(8)+R(2)
S(9)+I(4)+N(5)+C(6)+E(3)
--------------------------------
D(1)+A(0)+R(2)+W(3)+I(4)+N(5)=15

Ahh wats that calculation totally confused !! Can anyone plz tell me wat kind of qus it is??

@ bagish ::: since cant be more than 5 numbers.

ever = 5653
since= 97825
Darwin=103478

so D+a+r+w+i+n = 23

a=1,d=4,w=23,r=18,i=9,n=14 total=69*no of letters in the word

1 2 3 4 5 6 7 8 9 0
a b c d e f g h i j
k l m n o p q r s t
u v w x y z

by this u can see that
e=5, v=2, e=5, r=8
s=9, i=9, n=4, c=3, e=5

hence numbers must be unique for each alphabet

5 2 5 8
+9 9 4 3 5
---------------
1 0 4 6 9 3
d a r w i n

ans : 1+0+4+6+9+3=23