Latest A website Aptitude Question SOLUTION: One guy has Rs. 100/- in hand. He has to buy 100 balls. One football costs Rs. 15/, One Cricket ball costs Re. 1/- and one table tennis ball costs Rs. 0.25 He spend the whole Rs.

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(#M40032468) A WEBSITE Numerical Ability question Problem Keep an EYE

One guy has Rs. 100/- in hand. He has to buy 100 balls. One football costs Rs. 15/, One Cricket ball costs Re. 1/- and one table tennis ball costs Rs. 0.25 He spend the whole Rs. 100/- to buy the balls. How many of each balls he bought?

Asked In A website (10 years ago)

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Read Solution (4) :

Devendra Marghade  (10 years ago)

Football=3,Cricket ball=41 & Table tennis ball=56
If Number of Football=x,Cricket ball=y & Table tennis ball=z, then
x+y+z=100 ---(i) &
15x+y+0.25z=100 ---(ii)
Substituting value of z=100-(x+y) from (i) in (ii),we have 59x+3y=300 ---(iii)
For Equation (iii)satisfies the condition with x=3,y=41
So z=56

Is this solution Helpfull? Yes (6) | No (6)  

SHAHEEN  (9 years ago)

If Number of Football=x,Cricket ball=y & Table tennis ball=z, then
x+y+z=100 ---(i) &
15x+y+0.25z=100 ---(ii)
Substituting value of z=100-(x+y) from (i) in (ii),we have 59x+3y=300 ---(iii)
For Equation (iii)satisfies the condition with x=3,y=41
So z=56
Foot=3,Cricket=41 & tennis ball=56

Is this solution Helpfull? Yes (4) | No (4)  

Rekha  (8 years ago)

football: 3
cricket ball: 41
table tennis ball: 56

Is this solution Helpfull? Yes | No (4)  

neeraj kumar  (4 years ago)

suppose we want 100 balls in Rs. - 100. So from here, we got two-equation
15X+Y+0.25Z=100, and X+Y+Z=100
after solving these two equations we get X/Z=3/56
So X = 3 , Z = 56, and Y = 100-X-Y = 41
3 football , 56 tennis ball , 41 cricket ball
Let's verify 15*3 + 56*0.25 + 41*1=100 and 3+56+41=100

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