Latest Elitmus Aptitude Question SOLUTION: A can do as much work as C in 2 days and C does in 3 days as much work as B in 4 days. What time B would require to do a work which A can do in 16 weeks?

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(#M40032987) ELITMUS Numerical Ability question Time and work Keep an EYE

A can do as much work as C in 2 days and C does in 3 days as much work as B in 4 days. What time B would require to do a work which A can do in 16 weeks?

Asked In Elitmus Ankit Boae (10 years ago)

Unsolved Read Solution (12)

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Read Solution (12) :

LOKESH SAMANT  (10 years ago)

let A,B,C works is x,y,z
so 1/x=2/z---(I)
3/z=4/y-------(II)

1/x=1/16---(III)
from all the euatn
z=3*y/4
so 1/x=8/3*y

1/16= 8/3*y
y=16*8/3 weeks

Is this solution Helpfull? Yes (20) | No (1)  

Abhishek Mohanty  (8 years ago)

efficiency of A:C=2:1.
efficiency of C:B=4:3.
So, efficiency of A:C:B=8:4:3.
so efficiency of A:B=8:3.
so time taken by A:B=3:8=16:B
===>B=(128/3)=42*(2/3) weeks.

Is this solution Helpfull? Yes (10) | No   

Avinash Kumar  (10 years ago)

A(2 day's work)=c(3 day's work)
A(16*7 days work)=c(3*16*7/2)day's=168 days
C(3 Days work)=B(4 day's work)
C(168 Day's work)=B(4*168/3)=224 Days

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Nandan Kumar  (8 years ago)

298.66 DAYS

Is this solution Helpfull? Yes (3) | No (1)  

suraj kumar singh  (9 years ago)

A = 2C
3C=4B
C=(4/3)B
A=2*(4/3)B=(8/3)B or B=(3/8)A
A can do a piece of work in 16*7 days.
(3/8)A can do the sme piece of work in --------
(less/more)*(16*7)
((3/8)A)/A*(16*/7)=21days=3weeks.

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aaditya dwivedi  (8 years ago)

a:b = 2:1
b:c=4:3
so , A:B:C = 2:4:3
Now acc to question ,
a:b = 2:4
and
the weeks are 16 ,so days is 16*7=112 days
so , diff btw ratio of a:b is 2 .so divide 112/2 = 56
now multiply ratio of A&B with 56
a:b = 2:4
=>2*56 : 4*56
112 days(16 weeks) : 224 days (32 weeks )
so the answer is 32weeks i.e 224 days
its by efficiency method

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karunya  (9 years ago)

A can do as much as wrk in 2 days so A:C=1:2,In the same way they have compared C and B,so C:B=3:5...Taking B as 20(Assumption 4*5)...C would be 12(4*3)...hence 12C:20B(C:B) As per ratio given..then take12C with respective to A(A:B)...then the 12C is 2 part in 1:2 and 1 is 6..so 6A:12C:20B.....so ans is more than 55 weeks

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Mustkeem Khan  (9 years ago)

correct answer is 42 week 4 days

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Sandeep  (8 years ago)

A's 1 week work=1/16
C's 1 week work=1/32
B's 1 week work=3/(32*4)
B complete the work in 128/3 week.

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mayank shekhar jha  (8 years ago)

The % of Work Done By A=100/20=5% in one Minute.
The % of Work Done By B=100/30=3.33% in one Minute.
The % of Work Done By C=100/15=6.67% in one Minute.
Hence % of Work Done By A+B+(-C) in one Minute=5+3.33-6.66=1.67%
How Soon Cistern be filled =100/1.67=59.88
minutes=59.88*3=179.6 minutes=180 minutes.

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MD FAIZ AHMED  (6 years ago)

radius would be r/5 and height would h/5 , and the variable term is sqr(r)*h and hence 25*5=125 . Therefore ans is - 1:125

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arshiya  (6 years ago)

person A B C
days 2 4 3
L.c.m of 2,4,3 is 12
so cosider 12 units of work
A can do 12/2=6 units in a day
B can do 12/4=3 units in a day
c can do 12/3=4 units in a day
A in 1 day can do 6 units of work, so in 16 weeks A can do 16*7*6=672 units.
B in 1 day can do 3 units of work,so 672 units in 672/3=224 days(32 weeks)

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