Latest TCS Aptitude Question SOLUTION: The numbers 272738 and 232342, when divided by n, a 2 digit number, leave a remainder of 13 and 17 respectively. Find the sum of the digits of n? a. 7 b. 8 c. 5 d. 4

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(#M40033486) TCS Numerical Ability question Keep an EYE

The numbers 272738 and 232342, when divided by n, a 2 digit number, leave a remainder of 13 and 17 respectively. Find the sum of the digits of n?
a. 7
b. 8
c. 5
d. 4

Asked In TCS akshitha (10 years ago)

Unsolved Read Solution (9)

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Read Solution (9) :

RAKESH  (10 years ago)

as remainder is 13 & 17 so dividend must be greater than 17

272738 = n*a+13 => 272725=n*a ---(1)
232342 = n*b+17 => 232325=n*b ---(2)

last two digit of (1)&(2) is 25 so n must be 25, no other two digit no. greater than 25 satisfies this

272725=25*10909
232325=25*9293

n=25, sum of digits of n = 2+5 = 7

Is this solution Helpfull? Yes (69) | No (5)  

pramod  (10 years ago)

ans is 7
subtracting 272738 with remainder will make a divisible number.
so 272738-13=272725
dividing 272725 with 5,we get 54545,and again diving by 5 we get 10909
so the divided number is 5*5=25
hence the sum of the nuber is 7

Is this solution Helpfull? Yes (14) | No (1)  

Santosh Kumar  (10 years ago)

13 and 17 comes from the last two digits of given numbers
272738-xxxx25=13 , 232342-xxxx25=17

Is this solution Helpfull? Yes (9) | No (3)  

Selvi Raju  (10 years ago)

option: a
272738/n=13->272738-13=272725 it is divide by 25
232342/n=17->232342-17=232325/25
so sum of digit is 7

Is this solution Helpfull? Yes (3) | No   

jagriti singh  (8 years ago)

as remainder is 13 & 17 so dividend must be greater than 17

272738 = n*a+13 => 272725=n*a ---(1)
232342 = n*b+17 => 232325=n*b ---(2)

last two digit of (1)&(2) is 25 so n must be 25, no other two digit no. greater than 25 satisfies this

n=25, sum of digits of n = 2+5 = 7

Is this solution Helpfull? Yes (1) | No   

sourav biswas  (10 years ago)

ans- 25
2+5=7

Is this solution Helpfull? Yes | No (8)  

RITESH KUMAR  (10 years ago)

121-130 5's =1
131-140 =1
141-150 =2
151-160 =10
161-170 =1
171-180 =1
so,121-200 = 18
201-300 = 21
301-356 = 12
total = 51

Is this solution Helpfull? Yes | No (6)  

Arpit Rawat  (10 years ago)

rakesh pls provide correct sol for this

Is this solution Helpfull? Yes | No (2)  

rishabh jain  (10 years ago)

ans is a.

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