Latest Infosys Aptitude Question SOLUTION: Every day a cyclist meets a train at a particular crossing. The road is straight before the crossing and both are traveling in the same direction. Cyclist travels with a speed of 1

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Every day a cyclist meets a train at a particular crossing. The road is straight before the crossing and both are traveling in the same direction. Cyclist travels with a speed of 10 Kmph. One day the cyclist comes late by 25 min. and meets the train 5km before the crossing. What is the speed of the train.

Asked In Infosys Dhruv Gupta (14 years ago)

Solved Dr.Dipin Singh Read Solution (11)

Is this Puzzle helpful?   (37)   (18) Submit Your Solution Mathematical Reasoning

Read Solution (11) :

Dr.Dipin Singh  (14 years ago)

Let the initial gap be x and speed of train be v.

then

meeting point from cyclist = 10x/(v - 10)

On that particulate day.. initial gap = (x - 5v/12)

so

(10x/(v - 10)) - 5 = 10(x - 5v/12)/(v - 10)

10x - 5v + 50 = 10x - 50v/12

5v - 50v/12 = 50

60v - 50v = 12*50

10v = 600

v = 60 km/hr

Is this solution Helpfull? Yes (21) | No (11)  

SAKSHI AGARWAL  (12 years ago)

hi dipin..i exactly didnt get the solution of this puzzle. will u xplain it once more?

Is this solution Helpfull? Yes (13) | No (2)  

maniraj  (10 years ago)

Cyclist and Train meet at 5 km point.

If cyclist had left on time, they would be 25 min at 10km/h further
10km/h * 25/60 h = 25/6 km

This leaves the cyclist 5/6 km from the cross road, when the train is at 5 km

Time cyclist takes to travel this 5/6 km = distance / speed

(5/6) / 10 = 1 / 12 hours

The train travels 5 km in 1/12 h

speed = distance / time

5 / (1/12) = 5 * 12 = 60 km / h

Is this solution Helpfull? Yes (11) | No (4)  

Eshu  (14 years ago)

99090

Is this solution Helpfull? Yes (6) | No (21)  

Vadivelan M  (14 years ago)

60kmph

Is this solution Helpfull? Yes (4) | No (4)  

Tijo Jose  (14 years ago)

yes. It is 60 kmph

Is this solution Helpfull? Yes (2) | No (3)  

Sunil Tanwar  (14 years ago)

12kmph

Is this solution Helpfull? Yes (2) | No (12)  

C.T.Narayanan  (14 years ago)

22 km/hr

Is this solution Helpfull? Yes (1) | No (6)  

devender singh saini   (14 years ago)

let x =speed of train. and it is less than speed of cycle
5/10-x=25/60

Is this solution Helpfull? Yes (1) | No (9)  

devender singh saini   (14 years ago)

let us assume x=speed of train
then by question:-
(5/(10-x))=25/60
x=2kmph

Is this solution Helpfull? Yes (1) | No (21)  

sunny  (9 years ago)

time=distance/speed time=25min=25*60 hours, distance 5 km, speed of cycle is 10kmph and let trains is xkmpr.

apply formula
5/(X-10)=25*60
x=60kmph

Is this solution Helpfull? Yes (1) | No (5)  

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