Latest Infosys Aptitude Question SOLUTION: APPLE+PEAR=GRAPE.THEN G+R+A+P+E=?

@ rajeev is right.
I am trying to explain it..
See,1)since E+R=E --> R must be zero.
2)Since, A is giving G as addition, so G must be one more than A or A+1=G.
which also implies that P+P must add upto 10 or more than that.
3)Also,since R=0,it means P+P must be 10-->P=5.
4)Now, we have R=0,P=5.
5)Since L+A is giving p and there is no carry from E+R(because E could be 9 maximum).So,to have 5 we can have various permutations as (1,4),(4,1),(3,2)(2,3), and for greater than 10,we have(8,7),(7,8),(9,6),(6,9).
so the problem now is that what should be the correct one for L,A.
5.1) If we take (1,4) then A will be 4, but while calculating p+E=A,we have take E=9 and P=5(already calculated),but it will give us a carry for calculating P+P, which should not be there because P+P should be 10 only.Similarly, all the possible permutations adding to 5 are also not permitted.
5.1)So, we have to add L+A upto 15.If we take,A=8 and L=7, then there will be no problem at all,because P+E=A, and we can take E=2. So,Finally A could be taken as 8 to give G as 9.
hence,solved.
so,A=8,P=5,L=7,R=0,E=2,G=9.
I hope you have understand it.

APPLE
PEAR
-----
GRAPE
-----

85572
5280
------
90852
-----
9+0+8+5+2=24

Please explain clearly no one is explaining the concept of it.plz if any body knows the exact concept explain clearly

APPLE
+PEAR
----------
GRAPE
---------

75581
+5170
-------
80751
------

E+R=E => R=0 so, P+P=R=0 => P=5
so, 5+E=A & L+A=P => A IS GREATER 6 A=7 OR 8 etc

G+R+A+P+E=8+0+7+5+1=21

Answer is 24
APPLE
PEAR
-----
GRAPE
so these alphabets can be anything between 0-9 bt no two alphabets have same number.
so as per above equ E+R=E =>R=0
Since A has a carryout from its previous (sum p+p)
so A+1=G-----eq1
since P+P=10+R =>P=5
so We will have eqns like 5+E=A and L+A=5 Since A>5 so L+A is not equal to 5 it should be L+A=10+5 so 5+E+1=A ( 1 is the carryout from its previous sum(L+A))
from 5+E+1=A the possibilities of A would be 7,8,9
and A Cannot be 9 because A+1=G Will have contradiction that G=10 so A is not 9
so a and l can be 7 or 8 to satisy the eqn(a+L=15)
so if a is 7 , g would be 8 and l cannot be 8 so a is not 7
therefore a is 8 which solves the problem
as
apple =85572
pear=5280
grape=90852

Answer is 24
APPLE
PEAR
-----
GRAPE
arrange the letters as we do normally for numeric (from unit digits)
so these alphabets can be anything between 0-9 bt no two alphabets have same number.

so as per above equ E+R=E =>R=0
Since A has a carryout from its previous (sum p+p)
so A+1=G-----eq1
since P+P=10+R =>P=5
so We will have eqns like 5+E=A and L+A=5 Since A>5 so L+A is not equal to 5 it should be L+A=10+5 so 5+E+1=A ( 1 is the carryout from its previous sum(L+A))
from 5+E+1=A the possibilities of A would be 7,8,9
and A Cannot be 9 because A+1=G Will have contradiction that G=10 so A is not 9
so a and l can be 7 or 8 to satisy the eqn(a+L=15)
so if a is 7 , g would be 8 and l cannot be 8 so a is not 7
therefore a is 8 which solves the problem
as
apple =85572
pear=5280
grape=90852

A+P+P+L+E = 7+5+5+8+1
P+E+A+R = 5+1+7+0
G+R+A+P+E = 8+0+7+5+1 = 21

Answer: 12

Answer :12

Please Explain Clearly

APPLE+PEAR=GRAPE=25174
A=1,R=0,L=6,E=4,P=7,R=5,G=2.
17764+7410=25174.

consider each letter as a variable and assign values for each variable like A=8;P=5;L=6 and E=1 also for PEAR,where R is new letter not in APPLE, so R=4 and add these nos together(85561+5184=90745;)then add individual no:s like 9+0+7+4+5;

APPLE=85572
PEAR=5280
GRAPE=90852
SO 9+0+8+5+2=24

35572+5280=40852

4+0+8+5+2=19

@mukesh
I am trying to explain it..
See,1)since E+R=E --> R must be zero.
2)Since, A is giving G as addition, so G must be one more than A or A+1=G.
which also implies that P+P must add upto 10 or more than that.
3)Also,since R=0,it means P+P must be 10-->P=5.
4)Now, we have R=0,P=5.
5)Since L+A is giving p and there is no carry from E+R(because E could be 9 maximum).So,to have 5 we can have various permutations as (1,4),(4,1),(3,2)(2,3), and for greater than 10,we have(8,7),(7,8),(9,6),(6,9).
so the problem now is that what should be the correct one for L,A.
5.1) If we take (1,4) then A will be 4, but while calculating p+E=A,we have take E=9 and P=5(already calculated),but it will give us a carry for calculating P+P, which should not be there because P+P should be 10 only.Similarly, all the possible permutations adding to 5 are also not permitted.
5.1)So, we have to add L+A upto 15.If we take,A=8 and L=7, then there will be no problem at all,because P+E=A, and we can take E=2. So,Finally A could be taken as 8 to give G as 9.
hence,solved.
so,A=8,P=5,L=7,R=0,E=2,G=9.



here u told that A=8 then E should be 3
coz P+E=a
P=5
A=8
then E must be 3.

ALL answers for this type of questions

http://www.gtoal.com/wordgames/alphametic/testscript.out

plz explain clearly

From crypt-arithmetic procedure I got 19 as an answer.

From crypt-arithmetic procedure I got

G=9;
R=0;
A=8;
P=5;
E=2;

G+R+A+P+E=24.