Latest CAT Aptitude Question SOLUTION: How many zeros will be there at the end of expression:- (2!)^2!+(4!)^4!+(8!)^8!+(10!)^10!+(12!)^12!

• Placement Papers
• /
• CAT
• /
• Numerical Ability

CAT Question Papers:

(#M40033816) CAT Numerical Ability question progression Keep an EYE

How many zeros will be there at the end of expression:-
(2!)^2!+(4!)^4!+(8!)^8!+(10!)^10!+(12!)^12!

Asked In CAT MD SOHAIL AKHTER (10 years ago)

Unsolved Read Solution (1)

Is this Puzzle helpful?   (2)   (1) Submit Your Solution

Read Solution (1) :

RAKESH  (10 years ago)

(2!)^2!+(4!)^4!+(8!)^8!+(10!)^10!+(12!)^12!

= 2^2 + 24^24 + (8!)^8!+(10!)^10!+(12!)^12!

last two digit of (8!)^8!+(10!)^10!+(12!)^12! = 0 as each has a factor 10.

so, last two digit of (2!)^2!+(4!)^4!+(8!)^8!+(10!)^10!+(12!)^12! = 04 + 76 = 80

last two digit is 80
no. of zeroes at end = 1

Is this solution Helpfull? Yes (6) | No   

Please Login to Read Solution.