Latest TCS Aptitude Question SOLUTION: 3 persons A, B and C are standing in a queue. There are 5 persons between A and B and 8 persons between B and C. If there are 3 persons ahead of C and 21 persons behind A, what cou

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Permutation and Combination

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40033848) TCS Numerical Ability question TCS Keep an EYE

3 persons A, B and C are standing in a queue. There are 5 persons between A and B and 8 persons between B and C. If there are 3 persons ahead of C and 21 persons behind A, what could be the minimum number of persons in the queue ?
Option
1) 41
2) 40
3) 28
4) 27

Asked In TCS sree (10 years ago)

Unsolved Read Solution (22)

Is this Puzzle helpful?   (59)   (18) Submit Your Solution Permutation and Combination

Read Solution (22) :

judy tresa  (10 years ago)

positions : ---c--a-----b---------------
totally 28
ans is c

Is this solution Helpfull? Yes (66) | No (9)  

abhinay yadav  (10 years ago)

arrangement is like this
B
5 person
A
3 person
c
17person
plz include A,B,C while calculating answer
so answer is 21+A+5+B which means 21+1+5+1=28
option (3)

Is this solution Helpfull? Yes (30) | No (8)  

Shruti  (9 years ago)

Ans is 28.
The sequence of persons are:
3
C
2
À
5
B
15

Is this solution Helpfull? Yes (12) | No (1)  

sruthi  (9 years ago)

sorry, this is the right answer=28
Justification:
Three persons A, B, C can be arranged in a queue in six different ways i.e., ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements i.e., CBA and CAB. We may consider the two cases as under :
3 8 5 21
Case I : ← C ↔ B ↔ A →
clearly, number of persons in the queue = (3 + 1 + 8 + 1 + 5 + 1 + 21) = 40.
3 5
Case II : ← C A ↔ B



Number of persons between A and C = (8 - 6) = 2.
Clearly, number of persons in the queue = (3 + 1 + 2 + 1 + 21) = 28.
Now, 28 < 40. So, 28 is the minimum number of perosn in the queue.

Is this solution Helpfull? Yes (12) | No   

Aakash Jain  (10 years ago)

40=5+8+3+21 and +3(itself A,B and C)

Is this solution Helpfull? Yes (9) | No (10)  

Sharvil Mayekar  (9 years ago)

The queue structure:
(3persons)-C-(8persons)-B-(5persons)-A-(21persons)
minimum is the addition of all the persons including C,B,A which is: 3+1+8+1+5+1+21=40
ans is (2)-40

Is this solution Helpfull? Yes (5) | No   

sruthi  (9 years ago)

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,A,1,2,3,4,5,B,1,2,3,4,5,6,7,8,C,1,2,3====40 persons

Is this solution Helpfull? Yes (4) | No (1)  

chaitra  (10 years ago)

since Q is about minimum answer is 28

Is this solution Helpfull? Yes (3) | No (1)  

Nisha  (10 years ago)

ans= 2 i.e 40 persons

Is this solution Helpfull? Yes (2) | No (2)  

ranjan kumar  (9 years ago)

since the order is not given we will arrrange it in such an order that it will give its min value so..
if 21 +3(a b and c)+ 3=27 ans

Is this solution Helpfull? Yes (2) | No   

Goldi kumari  (9 years ago)

p1,p2......p21 A p1,p2...p5 B p1.....p8 C p1..p3
21+A+5+B+8+C+3
and A and B is also itself
21+1+5+1+8+1+3=40

Is this solution Helpfull? Yes (2) | No (2)  

poojitha  (10 years ago)

21...a-----b--------c---
from the above fig. 21+a counts 1 place+5+1+8+1+3=40

Is this solution Helpfull? Yes (1) | No (3)  

rahul  (9 years ago)

arrangement
3
c
3
a
5
b
16

=27

Is this solution Helpfull? Yes (1) | No (3)  

Shreya Banerjee  (9 years ago)

Three persons A, B, C can be arranged in a queue in six different ways i.e., ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements i.e., CBA and CAB. We may consider the two cases as under :
3 8 5 21
Case I : ← C ↔ B ↔ A →
clearly, number of persons in the queue = (3 + 1 + 8 + 1 + 5 + 1 + 21) = 40.
3 5
Case II : ← C A ↔ B



Number of persons between A and C = (8 - 6) = 2.
Clearly, number of persons in the queue = (3 + 1 + 2 + 1 + 21) = 28.
Now, 28 < 40. So, 28 is the minimum number of perosn in the queue.

Is this solution Helpfull? Yes (1) | No   

ranjan kumar  (9 years ago)

according to question..
21 a 5 b 8 c 3
so..21+5+8+3+3(a b and c)=40 as total

Is this solution Helpfull? Yes | No (1)  

OUJASWAEE DAS  (9 years ago)

40 as the sum would be 21 + 1+5+1+8+1+3= 40

Is this solution Helpfull? Yes | No (1)  

priyanka banerjee  (9 years ago)

21+1+5+1+8+1+3=40
ans is 40

Is this solution Helpfull? Yes | No (3)  

Ankit  (9 years ago)

- - - c- - a- - - - -b- - - - - - - - - - - - - - -

Is this solution Helpfull? Yes | No   

swati gupta  (9 years ago)

40
3 ahead of c+8 between B and c+5 between a and b+21 behind a + A,B,C themselves
so altogether 40

Is this solution Helpfull? Yes | No   

Shreya Banerjee  (9 years ago)

Three persons A, B, C can be arranged in a queue in six different ways, ie ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements, ie CBA and CAB.
We may consider the two cases as under:
Case I:
Clearly, number of persons in the queue = (3+1+8+1+5+1+21=) 40
Case II:
Number of persons between A and C
= (8 - 6) = 2
Clearly number of persons in the queue = (3+1+2+1+21) = 28

Now, 28 < 40.

So, 28 is the minimum number of persons in the queue.

Is this solution Helpfull? Yes | No   

rohini  (9 years ago)

cant understand the spacing between c and a as 2

Is this solution Helpfull? Yes | No   

NERELLA VENKATA LOKESHWAR  (8 years ago)

arrangement
3
c
3
a
5
b
16

=27

Is this solution Helpfull? Yes | No (1)  

Please Login to Read Solution.