Latest CAT Aptitude Question SOLUTION: Two taps a and fill a tank respectively in 6 and 8 min. if these two taps are opened one by one for one min each then how long will it take for the tank to fill up?

• Placement Papers
• /
• CAT
• /
• Numerical Ability
• /
• Time and Work

CAT Question Papers:

(#M40034670) CAT Numerical Ability question pipes and cisterns Keep an EYE

Two taps a and fill a tank respectively in 6 and 8 min. if these two taps are opened one by one for one min each then how long will it take for the tank to fill up?

Asked In CAT ramakrishna (10 years ago)

Unsolved Read Solution (4)

Is this Puzzle helpful?   (2)   (0) Submit Your Solution Time and Work

Read Solution (4) :

Ann Theressa  (10 years ago)

6 min 45 sec

In 1 min
1st tap fills =1/6
2nd tap fills =1/8

In 2 min they together fill = 1/6 +1/8 = 14/48=7/24
In 6 min they fill = 7/24*3 =21/24

Remaining fraction to be filled = 3/24 = 1/8

For 1st pipe
1/6 filled ---- 1min
1/8 filled -----x min
x = 6/8 min = 45 sec

Time taken to fill tank = 6 min 45 sec

Is this solution Helpfull? Yes (1) | No   

sravani  (9 years ago)

For 1 min 1/6th willbe filled.
For 2mins 1/6 + 1/8 = 7/24 will be filled.
for 4 mins 14/24
for 6mins 21/24 will be filled...
In 7th min 1/6 will be filled but need is only 1 - 21/24 =1/8
so let x be the time ...
x(1/6)=1/8
X=3/4 mins =3/4 * 60 =45 secs..
so, a total of 6mins 45 secs is required to fill the tank...

Is this solution Helpfull? Yes (1) | No   

Ann Theressa  (10 years ago)

48/7 min

In 1 min
1st tap fills =1/6
2nd tap fills =1/8

In 2 min they together fill = 1/6 +1/8 = 14/48=7/24

Time taken to fill tank = 24/7*2 = 48/7 minutes

Is this solution Helpfull? Yes | No (1)  

P.Someshwar Reddy  (10 years ago)

There are two solutions for this question.

Since it is not given which tap is opened first
i)if tap A is opened first then it takes 6 min 45 sec

6 min 45 sec

In 1 min
1st tap fills =1/6
2nd tap fills =1/8

In 2 min they together fill = 1/6 +1/8 = 14/48=7/24
In 6 min they fill = 7/24*3 =21/24

Remaining fraction to be filled = 3/24 = 1/8

For 1st pipe
1/6 filled ---- 1min
1/8 filled -----x min
x = 6/8 min = 45 sec

Time taken to fill tank = 6 min 45 sec

ii) if tap B is opened first then it takes 7mins

In 1 min
1st tap fills =1/6
2nd tap fills =1/8

In 2 min they together fill = 1/6 +1/8 = 14/48=7/24
In 6 min they fill = 7/24*3 =21/24

Remaining fraction to be filled = 3/24 = 1/8

For 2nd pipe
1/8 is filled in 1 min

Time taken to fill tank = 7mins

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.