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(#M40035247) TCS Logical Reasoning question maths Keep an EYE

Find the sum of even divisors of 4096.

Asked In TCS Subrata Patra (11 years ago)

Solved RAKESH Read Solution (14)

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Read Solution (14) :

RAKESH  (11 years ago)

4096 = 2^12

sum of even divisors = 2^1+2^2+2^3+...+2^12 = (2^13-2)

Is this solution Helpfull? Yes (28) | No (2)  

neha  (10 years ago)

2^1+2^2+2^4......+2^12
the series is in geometric series....
so the sum of g.m=a(r^n-1)/(r-1)
a=first term
r=common ratio..
n=12
since 4096=2^12
a=2
r=4
ans=2^13-2

Is this solution Helpfull? Yes (7) | No (6)  

Nikita Jain  (10 years ago)

first find out the divisors or factors of 4096 by taking LCM then all the factors like 2^12 then it will be written (2^0+2^1+2^2...+2^12)but when we have to find even divisors then eliminating 2^0 from above expression and sum up all the values and get ans as 8190.....

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mohammad vanak  (11 years ago)

rakesh plz explain

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Mayank  (10 years ago)

sum of even divisors = 2^1+2^2+2^3+...+2^12 = 2^12
by using sum of Gp

Is this solution Helpfull? Yes (2) | No (2)  

narapureddyyallareddy  (10 years ago)

8190
except 2^0(even divisors)
2^1+.......+2^12

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DHIRAJ KUMAR SINGH  (10 years ago)

2^12=4096
13 ans

Is this solution Helpfull? Yes (1) | No (3)  

nassarshahab  (11 years ago)

4096/19=215

Is this solution Helpfull? Yes | No (6)  

mohit tuteja  (10 years ago)

it is a G.P.
2,4,8,16,32....4096
sum of G.P. is 4094=2^12-2

Is this solution Helpfull? Yes | No (1)  

Mohit Dayal Gupta  (10 years ago)

Its factors are 2,4,8,16,32,64,128,256,512,1024,2048,4096. Howi calculated this?? firstly we have to find out the factors till half of the square divisor of 4096. Since 60*60=3600 and 70*70=4900 so we have to find factors till 60-70. So i started calculating from 2,2*2048, 4*1024, 8*512 since these all are factors in the form of powers of 2, i calculated all the factors by simple guessing.

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ASIPI RAVI  (10 years ago)

4096=2^12
even divisors are 2,4,8,16,32,64,128,256,512,1024,2048
i.e. 2^1,2^2,2^3,2^4,2^5,2^6,2^7,2^8,2^9,2^10,2^11
the sum of these numbers is: (2^12)-2 =4094

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Aniruddha  (10 years ago)

the factors are 2^0,2^1,2^2,.....,2^12
so sum o the factors will be 2^13-2

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peravali yesaswi  (10 years ago)

what is the remainder when 48^565 divided by 7? todays my tcs question

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shashidharhiremath  (10 years ago)

4096=2^12
so total number of factors will be 12+1=13
so sum=2^13-2

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