Latest TCS Aptitude Question SOLUTION: when a number divided by D leaves remainder of 8and when by 3D leaves remainder of 21.what is the remainder left,when twice the number diveded by 3D. a-32 b-4567 c-3

• Placement Papers
• /
• TCS

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40003585) TCS question Keep an EYE

when a number divided by D leaves remainder of 8and when by 3D leaves remainder of 21.what is the remainder left,when twice the number diveded by 3D.

a-32
b-4567
c-3

Asked In TCS (12 years ago)

Unsolved Read Solution (4)

Is this Puzzle helpful?   (7)   (0) Submit Your Solution

Read Solution (4) :

Dr.Dipin Singh  (12 years ago)

3


Number is 21 and D is 13.
when 21 is divided by 13 leaves remainder of 8and when by 39 leaves remainder of 21.
3 is the remainder left
42 is divided by 39.

Is this solution Helpfull? Yes (11) | No (4)  

Vishnu Chand Gupta  (12 years ago)

Let number is n
and k,l,m are positive integers.

Then:
n=kd+8 (1)
n=l(3d) + 21 (2)
from above two equations:
(3*l-k)d+13=0
which means either d|13 or (k-3*l)|13
but d can't be 1 and 13 is prime so d=13

so,
n=13k+8, n=39*l+21
k,l >= 0, n is also integer,
k=1, l=0 is one solution (For which answer of question is 3)
and others are: k-3*l=1 or k=3*l+1

Is this solution Helpfull? Yes (3) | No (6)  

lalli  (12 years ago)

suppose the no. is a
a = Dx +8 ...1
a = 3Dy + 21 ...2
So from 1 & 2 we get
D(x-3y) = 13
13 is prime so x-3y has to be 1
let x = 4 and y = 1
We get a = 60
2a = 120
So 120 when divided by 3D = 39
we get remainder as 3
So answer is 3

Is this solution Helpfull? Yes (3) | No   

rajvir singh  (12 years ago)

ans is 3

the number is 60 and D=13
as 60/13=4 (remainder 8)
and 60/3*13=60/39=1 (remainder 21)
now 2x/3D=2*60/3*13=120/39=3 (3 remainder)

Is this solution Helpfull? Yes (1) | No   

Please Login to Read Solution.