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(#M40037465) TCS Numerical Ability question TCS Keep an EYE

JAZ, LEX, NIV, PMJ

- RQR
- RUS
- SUR
- PUR

Asked In TCS Sneh (10 years ago)

Solved alekhya gandhi Read Solution (11)

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Read Solution (11) :

alekhya gandhi  (10 years ago)

The series given in this question is wrong. in the last series it should not be PMJ . It should be PMT. Then the answer will be (a) RQR
1st consider the first alphabets in the series. J+2=L, L+2=N, N+2=P, P+2=R
2nd alphabet-> A+4=E, E+4=I, I+4=M, M+4=Q
3rd alphabet-> Z-2=X, X-2=V, V-2=T, T-2=R

Is this solution Helpfull? Yes (16) | No   

saikumar  (10 years ago)

consider the first alphabet in each word
i.e, "J" k "L" m "N" o "P" q "R"
and come to second alphabet of the given word in series of...
, "A" bcd "E" fgh "I" jkl "M" nop "Q"...
so finllay the answer is with RQ i.e RQR.

Is this solution Helpfull? Yes (3) | No   

Ruchi   (10 years ago)

isnt thr some problem with the last one:PMJ..shudnt it be PMT???

Is this solution Helpfull? Yes (2) | No   

VINU CHOWDARY  (10 years ago)

The series given in this question is wrong...
in given series at the end should not be PMJ.
It should be PMT. Then the answer will be (a) RQR
1st consider the first alphabets in the series. J+2=L, L+2=N, N+2=P, P+2=R
2nd alphabet-> A+4=E, E+4=I, I+4=M, M+4=Q
3rd alphabet-> Z-2=X, X-2=V, V-2=T, T-2=R

Is this solution Helpfull? Yes (1) | No   

SAHELI BISHNU  (10 years ago)

j (k) l (m) n (o) p (q) r
a ( b, c, d) e ( f,g,h) i (j,k,l) m (n,o,p) q
So RQR

Is this solution Helpfull? Yes (1) | No   

priyanka   (10 years ago)

in middle a next e next i next m next q differnce in three spaces letters
so answer RQR

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Ruchi   (10 years ago)

1st char has difference of 1...second of 5...so RQR

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LOKESH RANJAN  (10 years ago)

RQR,as sequence relates

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savita kumari  (10 years ago)

rqr is the correct answer

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LOKESH RANJAN  (10 years ago)

RQR, from sequence

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Tanu  (10 years ago)

RQR
J,L,N,P,R alternate sequence
A,E,I,M,Q diff of 3
no need to look for the 3rd sequence we can find the ans

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