Latest TCS Aptitude Question SOLUTION: Two identical circles intersect so thta their centres, and the points at which they intersect, form a square of side 1 cm. The area in sq.cm of the portion that is common to the tw

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Two identical circles intersect so thta their centres, and the points at which they intersect, form a square of side 1 cm. The area in sq.cm of the portion that is common to the two circles

Asked In TCS anuhya (10 years ago)

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karthikeyank  (10 years ago)

Ans:pi/2 -1
Area of the common portion can be calculated as = 2(Area of the sector of a circle having the angle of 90o - area of the right angled triangle of side 1 cm). Here the right angled triangle is obtained by joining the two intersecting points which is in turn the diagonal of the square.
Now the area of common section is = 2( (90/360)* pi * 1*1 - (1/2)*1*1)
=pi/2 -1

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Niveditha Ravichandran  (10 years ago)

area of the square = 1 sq cm
area of the sector of a circle when angle is provided = pi r^2 * angle /360
for a square the angle at all vertices is 90 deg
so pi*(1)^2* 90 / 360
= pi/4 ( this is for one circle)
for 2 circles = pi/2

total area of the 2 sectors of the circle = pi/2 ( this includes overlapped area)
so overlapped area = area of 2 sectors of circle - area of square
= pi/2 - 1

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ABHINAV DINGRE  (10 years ago)

π/2 -1
common area is reduced from area of quarter sector

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shashi kumar  (10 years ago)

0.57 sq cm

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Raghav gupta  (10 years ago)

please tell me how to draw the figure i cant visualize the figure

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