Latest TCS Aptitude Question SOLUTION: Two series, s1 and s2 each of 150 termare1,5,9......and 3,6,9.......respectively.how many terms of s1 and s2 are identical ?

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Arithmetic

TCS Question Papers: TCS Interview Experience(91) TCS Company Profile

(#M40039067) TCS Numerical Ability question Keep an EYE

Two series, s1 and s2 each of 150 termare1,5,9......and 3,6,9.......respectively.how many terms of
s1 and s2 are identical ?

Asked In TCS bhagwandas kushwaha (10 years ago)

Unsolved Read Solution (7)

Is this Puzzle helpful?   (37)   (12) Submit Your Solution Arithmetic

Read Solution (7) :

jhil  (10 years ago)

1,5,9,13,17,.....,(1+149*4=597)
3,6,9,12,15,....,(3+149*3=450)

series of common terms
9,21,33,45,... < = 450
tn=a+(n-1)d
put a=9 tn=441 d=12
ans n=37

Is this solution Helpfull? Yes (47) | No   

RAKESH  (10 years ago)

1,5,9,13,17,.....,(1+149*4=597)
3,6,9,12,15,....,(3+149*3=450)

series of common terms
9,21,33,45,... < = 450
=> n = 36 terms are identical

Is this solution Helpfull? Yes (13) | No (11)  

Rajdeep Sharma  (10 years ago)

450 is the last digit, not total term

Is this solution Helpfull? Yes (4) | No (2)  

anchal gupta  (10 years ago)

how tn=441

Is this solution Helpfull? Yes (3) | No (2)  

raviteja  (10 years ago)

how do u know that there are 450 common terms @rakesh

Is this solution Helpfull? Yes (2) | No (3)  

Raghav gupta  (10 years ago)

from how an=441......in series si and s2 we have to find the common one if we use 450 as the identical term then in series one 450 is not present as a+(n-1)d=450 is in fraction n can not be in fraction number should be divisible by putting 441 is correctly divisible in both the series

Is this solution Helpfull? Yes | No (2)  

Mayank Tiwari  (4 years ago)

There are 47 common between both series

Is this solution Helpfull? Yes | No (2)  

Please Login to Read Solution.