Latest Accenture Aptitude Question SOLUTION: Every man dances with 3 women and every woman dances with 3 men.And also 2 men have 2 women in common in the party. How many people attended the party?

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Every man dances with 3 women and every woman dances with 3 men.And also 2 men have 2 women in common in the party. How many people attended the party?

Asked In Accenture (12 years ago)

Unsolved Read Solution (5)

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Read Solution (5) :

Neha  (11 years ago)

Men -- M1, M2... etc
Women -- W1, W2.. etc

the pair can we arranged this way --

M1-W1; M1-W2; M1W3 -- FIRST PAIR

Now, we have a condition -- each men has exactly 2 women in common.
so, we need 1 extra woman for next pair

M2-W1; M2-W2; M2W4
LIKEWISE, WE CAN ARRANGE MEN FOR W4 AS WELL.

M3-W1; M3-W3; M3W4
Last Pair; -- M4-W2; M4-W3; M4-W4
TOTAL --

4 Men -- M1 M2 M3 M4
4 Women -- W1 W2 W3 W4 = 8

Is this solution Helpfull? Yes (11) | No (5)  

math  (10 years ago)

ans 4men & 4 women

m1-w1 w2 w3

m2-w1 w2 w4

m3-w3 w4 w1

m4-w2 w4 w3

Is this solution Helpfull? Yes (3) | No (2)  

Sumit Gupta  (11 years ago)

ans. 8....

Is this solution Helpfull? Yes | No (3)  

Dawood  (5 years ago)

4men & 4 women
m1-w1 w2 w3
m2-w1 w2 w4
m3-w3 w4 w1
m4-w2 w4 w3

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Rudra  (11 Months ago)

if 1M dance with 3 Womens and
1W dance with 3 mens then
this means that 3 mens are dance with 3 womens = 6 peoples ,
but now in the party 2 mens and 2 womens are present = 4 peoples are now present
then 6-4 = 2
add that 2 in the 6members then w will get the total number of people in the party they are = "8"

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