Latest TCS Aptitude Question SOLUTION: HOW MANY 4 DIGITS NUMBER DO NOT CONTAIN 3 OR 6

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HOW MANY 4 DIGITS NUMBER DO NOT CONTAIN 3 OR 6

Asked In TCS SHUBHAM SONI (10 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

Rohit  (10 years ago)

7*8*8*8=3584

Is this solution Helpfull? Yes (15) | No   

Rajdeep Sharma  (10 years ago)

suppose the "four digit" number is
"abcd"
now
"d " digit can be 0,1,2,4,5,7,8,9 =8ways
"c " digit can be 0,1,2,4,5,7,8,9 =8ways
"b " digit can be 0,1,2,4,5,7,8,9 =8ways

the turnig point is digit "a" can not have {0,3,6}
because if we use "0" then number becomes 3digit number
for example
"0124"

thats why

"a " digit can be 1,2,4,5,7,8,9 =7ways

so
answer is
7*8*8*8=3584

Is this solution Helpfull? Yes (9) | No   

gorijala swathi  (10 years ago)

2*8*9*9*9=11664

Is this solution Helpfull? Yes (2) | No (3)  

Sinchan Das  (10 years ago)

unit's place can filled in 6 ways except 0,3,6
and rest 7 ways except 3 or 6
so, 6*7^3

Is this solution Helpfull? Yes (1) | No (3)  

Deepanshu Batra  (10 years ago)

its '3 OR 6' not '3 AND 6'
but most of you have given the answers taking '3 AND 6'....
am confused ...
it has to be -->
no of 4 digit numbers not containing 3 +(OR) no of 4 digit numbers not containing 6
which is =8*9*9+8*9*9=2*8*9*9
Ans --> 2*8*9*9

Is this solution Helpfull? Yes (1) | No   

chandragupta sarkar  (10 years ago)

this can be done in 3 cases-
1- when 3 is not present then no of ways=8*9*9*9 (since repetition is allowed)
2- when 6 is not present den no of ways=8*9*9*9 (since repetition is allowed)
3- when 3 and 6 both are not present den no of ways- 7*8*8*8

total no of ways=sum of all three= 15248 ans.

Is this solution Helpfull? Yes (1) | No   

abhyuday pal  (10 years ago)

7*8*8*8
= 3584

Is this solution Helpfull? Yes | No (1)  

Sowmiya  (10 years ago)

ans is 3854

Is this solution Helpfull? Yes | No (1)  

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