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(#M40039190) TCS Numerical Ability question number system Keep an EYE

If all the factors of 5040 are written in ascending order then which will be 55th factor from beginning?

Asked In TCS pavithra (10 years ago)

Unsolved Read Solution (6)

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Read Solution (6) :

jaya chandra  (10 years ago)

the total factors are 5040=2^4*3^2*5*7=(4+1)(2+1)(1+1)(1+1)=60

so
1*5040
2*2520
3*1680
4*1260
5*1008
6*840
.....

55th factor is 840

Is this solution Helpfull? Yes (43) | No (3)  

Swayanti Bhaumik  (10 years ago)

840???
5040 has got 60 factors...
6*840=5040

Is this solution Helpfull? Yes (5) | No (1)  

Tirzah  (8 years ago)

5040 = 2^4 × 3^2 × 5^1 x 7^1

Number of divisors = (4+1)(2+1)(1+1)(1+1) = 60

So 55th factor from beginning is also the 6th factor from the end

60th = 5040
59th = 5040/2 = 2520
58th = 5040/3 = 1680
57th = 5040/4 = 1260
56th = 5040/5 = 1008
55th = 5040/6 = 840

Is this solution Helpfull? Yes (2) | No   

m.nagashilpa  (10 years ago)

5040 factors are ascending order 2,4,6,8,10........
these are in a.p
in a.p nth term is a+(n-1)d
so 55th term is 2+54(2)=110

Is this solution Helpfull? Yes (1) | No (16)  

Archana D R  (10 years ago)

Which is the right ans?

Is this solution Helpfull? Yes (1) | No   

saurav justin  (8 years ago)

the factor will be 2,4,6,8,10,12,14,16,18,20.......... here this series in a.p with first term 2 and cd=2
so 55Tth term will be =2+(55-1)*2=110. i think this is the correct answer.

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