Latest TCS Aptitude Question SOLUTION: 7 different objects are divided among 3 different person,so that either one or two of them do not get any object.how many such combinations are possible?

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(#M40039210) TCS Numerical Ability question permutations and combination Keep an EYE

7 different objects are divided among 3 different person,so that either one or two of them do not get any object.how many such combinations are possible?

Asked In TCS Priyanka Gaikwad (10 years ago)

Unsolved Read Solution (10)

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Read Solution (10) :

Arpan Balpande  (10 years ago)

Case 1 :
Two of them do not get any object,
this means all 7 Different objects is given to only one person.
But there are 3 different person hence

No. of ways (N1)= 3 Ways (007,070,700)

Case 2:
One of them do not get any object.

Hence the other 2 will get the 7 different objects.

This is done in 6 ways i.e (160,250,340,430,520,610)

again there are 3 different persons
hence
No. of ways (N2) = 3*6 = 18

Total no. of ways = N1+N2= 3+18 = 21

Is this solution Helpfull? Yes (12) | No (4)  

miraj ansari  (10 years ago)

here by prob we can say that if any 2 dont get any obj.total obj goes to 3rd person in 3 way.
if 1 of them dont get object then 7 object goes to 2 person

(1,6)=7c1

(2,5)=7c2

(3,4)=7c3

(4,3)=7c4

(5,2)=7c5

(6,1)=7c6

total 7c1+7c2+7c3+7c4+7c5+7c6=126

for 2 person two way=2*126=378

3rd person get the object in 3 way

so tatal =3+378=381 way Ans

Is this solution Helpfull? Yes (9) | No (10)  

manaswini devabhakthuni  (10 years ago)

if 2 dont get object then 7 objects will go to one person in 3ways...3c1
if 1 dont get obect then 7 objects go to 2 persons
(1,6)=7c1
(2,5)=7c2
(3,4)=7c3
(4,3)=7c4
(5,2)=7c5
(6,1)=7c6
total=126
2 persons is selected among 3 persons in 3c2 ways
hence 3*126+3=381

Is this solution Helpfull? Yes (6) | No   

Utsav Kumar  (10 years ago)

case 1: two of them do not get any object:
7C1=7 ways=7
case 2: one of them do not get any object:
7C2 * 3C2= 21*3=63
total combinations= 63+7=70

Is this solution Helpfull? Yes (1) | No (1)  

gaurav kumar  (10 years ago)

ans is 3^7
r^n here r is persons and n is different things

Is this solution Helpfull? Yes | No (3)  

NILESH KUMAR  (10 years ago)

ans is 84 as there will be two case case 1 if 1 person doesnot get anything in case no of combinations will be 3c1*7C2 and case 2 when 2 person will get nothing then no of combinations will be 3C2*7C1
so ans = 3C1*7C2+3C2*7C1 = 84

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Navya  (10 years ago)

can any one tell me the correct answer plz!

Is this solution Helpfull? Yes | No (1)  

priyanshi  (10 years ago)

since it is possible to give no objects to one of two person,then we would hv 3choices..for giving each item..3*3*3*3*3*3*3
2187

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vinod basnure  (10 years ago)

I guess, here we can select either of 1 and 2 in two ways,,
so we should use 2*7c2 == 42 is answer i guess..

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kundan karn   (10 years ago)

for 2 person two way=2*126=378

3rd person get the object in 3 way

so tatal =3+378=381 way

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