Latest CTS Aptitude Question SOLUTION: 4. 2,3,6,7--- using these numbers form the possible four digit numbers that are divisible by 4.

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(#M40039482) CTS Numerical Ability question number Keep an EYE

4. 2,3,6,7--- using these numbers form the possible four digit numbers that are divisible by 4.

Asked In CTS Roshni (9 years ago)

Unsolved Read Solution (12)

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Read Solution (12) :

archana  (9 years ago)

6732
7632
2736
7236
6372
3672
2376
3276

Is this solution Helpfull? Yes (13) | No (1)  

aabhas  (9 years ago)

if no are repeated
4C2(for 32 being last 2 digits)
4C2(for 36 being last 2 digits)
4C2(for 72 being last 2 digits)
4C2(for 76 being last 2 digits)
so 4*4C2=24
if repetition not allowed
2 ways for 32 being last 2 digits -->6732,7632
2 ways for 36 being last 2 digits--> 2736,7236
2 ways for 72 being last 2 digits--> 3672,6372

2 ways for 76 being last 2 digits--> 3276,2376

Is this solution Helpfull? Yes (7) | No   

Kalyani Reddy  (9 years ago)

Divisible by 4 means last 2 digits should divisible by 4
2376
3276
6732
7632
3672
6372
total 6

Is this solution Helpfull? Yes (6) | No (11)  

prasanthi  (9 years ago)

the digits divisible by 4 are 72,76,36,32. - - - - so the last 2 digits we can arrange 4 ways and the remaining 2 place we can arrange 2 1 so total 4*2=8 ways

Is this solution Helpfull? Yes (5) | No   

Naveen Kumar  (9 years ago)

if repeatation allowed ans=24
if not ans=16

last 2 digits should divisible by 4
--32
--36
--72
--76
if repeatation allowed
then selecting two digits from given four digits
4*4c2=24

if not
then selecting two digits from remaining two digits
2*2*2*2=16

Is this solution Helpfull? Yes (2) | No (2)  

siddhant sharma  (9 years ago)

3672 is the answer.

Is this solution Helpfull? Yes (1) | No (1)  

Sayan Dutta  (8 years ago)

if we take last 2 digits as 36 then der vil b 4x4 =16 no. possible..similarly in case of 32, 72 and 76...
so total 16x4=64 no. possible..

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ganesh chavan  (7 years ago)

8 only without repitition

Is this solution Helpfull? Yes (1) | No   

vivek kumar   (9 years ago)

36
since there are 6 pairs of no. which are divisible by 4 ; 76 , 72 , 64 , 36 , 32 , 24 and possible ways of filling the hundredth and thousand place is 3 * 2 so total no. of ways = 6 * 3 * 2

Is this solution Helpfull? Yes | No (1)  

prathiba  (9 years ago)

4,8,........100;
tn=a+(n-1)d
100=4+(n-1)4
96=4n-4
96+4=4n
100/4=n
n=25

Is this solution Helpfull? Yes | No (2)  

SREEDHAR  (9 years ago)

total given numbers 4.
divisible 4 means last 2 digits must divisible by 4
that last 2 digits together taking single digit total 3 parts of that number can be arranged by 3!=3*2*1=6 numbers are formed.

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niranjan  (8 years ago)

8 numbers...

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