Latest TCS Aptitude Question SOLUTION: The price of a commodity (in rupees per kg) is 100 + 0.1n, on the nth day of 2007(n=1,2,3....100) and then remains constant . on the other hand the price of another commodity( in r

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The price of a commodity (in rupees per kg) is 100 + 0.1n, on the nth day of 2007(n=1,2,3....100) and then remains constant . on the other hand the price of another commodity( in rupees per kg) is 89 + 0.15n , on the nth day of 2007( n=1,2,3,...365). On which date on 2007 will the price of these two commodities be equal?

Asked In TCS Loknath Sarkar (9 years ago)

Solved aman sharma Read Solution (7)

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Read Solution (7) :

aman sharma  (9 years ago) Best Solution

after 100th day it become const so max value for 1st eq. 100+.1*100 =110
110= 89+.15n
n=140
jan =31
and so onn.. 28,31,30
ans 20 may

Is this solution Helpfull? Yes (32) | No (3)  

guddu  (9 years ago)

110=89+0.15n
n=140
May 20

Is this solution Helpfull? Yes (6) | No (3)  

Kolluru Nagalakshmi  (9 years ago)

100+0.1n=89+0.15n
100-89=0.15n-0.1n
0.05n=11
n=11/0.05=11*100/5=220
hence 220th day price of two commodities equal
July 29 is 220th day

proof:
100+0.1(220)=89+0.15(220)
100+22=89+33
122=122

Is this solution Helpfull? Yes (6) | No (17)  

Subhadip  (9 years ago)

At the 100 the day the value of 1st commodity is 110 and 2nd commodity is 104.

So the eqn becomes
89+0.15n=110
=>.15n=110-89
=>n=140

So the total day is 100+140=240
The 243rd day is 31st July
240 th day becomes 28th July.

Is this solution Helpfull? Yes (2) | No   

iqbal siddiqui  (9 years ago)

explain in proper way so that we can understand

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Satyendra Kumar  (9 years ago)

After 100 day 1st commodity becomes
100+0.1*100=110
and second commodity becomes
89+0.15*100=104.
It means need more than 100 day to be a equal but 1st commodity constant after 100 day so equation becomes as
89+0.15n=110
after solving we get n=140day
140day/30 =4 month 20 days
so the day is 20 may.

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Loknath Sarkar  (9 years ago)

plz explain

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