Latest TCS Aptitude Question SOLUTION: find the no. of polynomial for degree of x>+1 where f(x2)=f(x)2=f(f(x))

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(#M40040635) TCS Numerical Ability question number polynomial Keep an EYE

find the no. of polynomial for degree of x>+1 where f(x2)=f(x)2=f(f(x))

Asked In TCS ANUP KUMAR GUPTA (9 years ago)

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