Latest L&T Aptitude Question SOLUTION: The rate of failure in an examination is 39.25%. Find the least number of total candidates appeared in the examination.

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The rate of failure in an examination is 39.25%. Find the least number of total candidates appeared in the examination.

Asked In L&T Priyanka Saha (9 years ago)

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alok meher  (9 years ago)

if 100 student appear then failure=39.25 ......... which is not possible because number of student can not be fraction,like wise in 200 student,failure=78.5, so we have to make the failure percentage into a unit digit failure not fraction...so min no of student =400 so that no of failure=157..........so least no of student appeared in the exam= 400.

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tirupathi reddy  (9 years ago)

39.25(out of 100 appeared) becomes integer value when multiplied by 4, 8, 12....
The least value is 4
Total appeared = 100*4 = 400

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Shiksha Tiwari  (9 years ago)

Gn. 39.25% rate of failure is there.
assume 10000 appeared, then 3925 failed
then, if 2000 appeared,then 785 failed// dividing by 5
then if, 400 appeared, then 157 failed // dividing by 5
after this 157/400 ratio wont produce whole no. fraction.
thus the required answer is 400.

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Anirban  (9 years ago)

We have to take care of the number should not be in fraction... As there is .25 in the last part of the digit so if we multiply it by 4 then it will become .25x4=1.00... So here we can see we can eliminate the fraction part by multiplying it with 4. So in 100 people 39.25% student has failed... So we can easily say that the least number of candidates will be 4x100= 400

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Chirag Ranjan Lahiri  (9 years ago)

39.25(out of 100 appeared) becomes integer value when multiplied by 4, 8, 12....
The least value is 4
Total appeared = 100*4 = 400

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