Latest Infosys Aptitude Question SOLUTION: a certain no. of workers can do a piece of work in 25 days,in what time will another set of equal no. of men do a piece of work as great supposing that 2 men of the first set can d

• Placement Papers
• /
• Infosys
• /
• Numerical Ability
• /
• Time and Work

Infosys Question Papers: Infosys Interview Experience(10) INFOSYS Company Profile

(#M40004376) INFOSYS Numerical Ability question infosys puzzle Keep an EYE

a certain no. of workers can do a piece of work in 25 days,in what time will another set of equal no. of men do a piece of work as great supposing that 2 men of the first set can do as much work in a hour as 3 men in the second set can do in a hour?
a)60days b)75days c)90days d)105days e)none

Asked In Infosys (12 years ago)

Unsolved Read Solution (3)

Is this Puzzle helpful?   (20)   (8) Submit Your Solution Time and Work

Read Solution (3) :

Dr.Dipin Singh  (12 years ago)

x persons of first group can do work in 25 days.

2 men of first group = 3 men of second group , then x persons of second group = 2x/3 persons of first group.

x persons of first group can do work in 25 days.
2x/3 persons of first group can do work in 25 *3/2 = 75/2 = 37.5 days .... none of given options ... so ..e)none

Is this solution Helpfull? Yes (19) | No (3)  

  (6 years ago)

2M1=3M2
efficiency = M1 :M2=3:2
No of men in 2nd set =N, Hours needed in 2nd set=H
total 1st set work= efficency*hour*men1 = 3*25*N

2(1st set work)= 2nd set work
2(3*25*N)=2*N*H
H = 75

Is this solution Helpfull? Yes (2) | No (1)  

Ponnambalam  (6 years ago)

2M1=3M2
efficiency = M1 :M2=3:2
No of men in 2nd set =N, Hours needed in 2nd set=H
total 1st set work= efficency*hour*men1 = 3*25*N

2(1st set work)= 2nd set work
2(3*25*N)=2*N*H
H = 75

Is this solution Helpfull? Yes (2) | No (1)  

Please Login to Read Solution.