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(#M40005534) IBM Numerical Ability question problems on numbers Keep an EYE

How many different factors are there for the number 48, excluding 1 and 48?

Asked In IBM (13 years ago)

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Sanjana Patnaik  (13 years ago)

48=2^4*3^1
Total No. of factors=5*2=10(each power of prime factor shall be increased by 1 and multiply)
Exculding 1 and 48, the No. of factors would be 8

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pratik kumar  (13 years ago)

To find the number of factors of a given number, express the number as a product of powers of prime numbers.

In this case, 48 can be written as 16 * 3 = (24 * 3)

Now, increment the power of each of the prime numbers by 1 and multiply the result.

In this case it will be (4 + 1)*(1 + 1) = 5 * 2 = 10 (the power of 2 is 4 and the power of 3 is 1)

Therefore, there will 10 factors including 1 and 48. Excluding, these two numbers, you will have 10 - 2 = 8 factors.

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Akash Vishnu Sangle   (8 years ago)

48 =2*2*2*2*3

4 times 2 so 4+1=5
1 time 3 so 1+1=2

Number of factors of 48= 5*2=10
Excluding 1 and 48
10-2= 8 ( Ans )

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