Latest IBM Aptitude Question SOLUTION: What is the probability of getting at least one six in a single throw of three unbiased dice?

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(#M40005589) IBM Numerical Ability question Probability Keep an EYE

What is the probability of getting at least one six in a single throw of three unbiased dice?

Asked In IBM (12 years ago)

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pratik kumar  (12 years ago)

for no 6 = 5*5*5 / 6*6*6 = 125/216

for atleast one 6 = 1-125/216 = 91/216.

Is this solution Helpfull? Yes (12) | No (2)  

princi  (12 years ago)

Find the number of cases in which none of the digits show a '6'.

i.e. all three dice show a number other than '6', 5 * 5 *5 = 125 cases.

Total possible outcomes when three dice are thrown = 216.

The number of outcomes in which at least one die shows a '6' = Total possible outcomes when three dice are thrown - Number of outcomes in which none of them show '6'.

= 216 - 125 = 91.

The required probability = 91/216

Is this solution Helpfull? Yes (9) | No   

HARSHITHA  (9 years ago)

P(getting a 6) = 1/6
P(not getting a 6 on one throw) = 5/6
P (not getting a 6 on three throws) = 5/6*5/6*5/6 = 125/216

P(getting at least a 6) = 1-125/216= 91/216

Is this solution Helpfull? Yes (4) | No   

vasuki  (9 years ago)

P(getting a 6) = 1/6
P(not getting a 6 on one throw) = 5/6
P (not getting a 6 on three throws) = 5/6*5/6*5/6 = 125/216

P(getting at least a 6)=1-125/216=91/216

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