Latest IBM Aptitude Question SOLUTION: A room has width half of its length. When 6 is decreased from both length and width then its area is differed by 108 so find the length.

• Placement Papers
• /
• IBM
• /
• Numerical Ability
• /
• Area and Volume

IBM Question Papers: IBM Interview Experience(49) IBM Company Profile

(#M40000564) IBM Numerical Ability question fine the room lenght Keep an EYE

A room has width half of its length. When 6 is decreased from both length and width then its area is differed by 108 so find the length.

Asked In IBM Aditi Sharma (13 years ago)

Solved Sumandeep Ghosh Read Solution (8)

Is this Puzzle helpful?   (38)   (11) Submit Your Solution Area and Volume

Read Solution (8) :

Sumandeep Ghosh  (13 years ago)

let length = x n width = x/2
so as per question
{(x*x/2)-(x-6)(x/2-6)}=108
so after solving 9x =144
x=16
so length is 16..

Is this solution Helpfull? Yes (95) | No (7)  

Sanathkumar  (13 years ago)

Answer is legth=16; Because if we consider length as x then width is (x/2).Area will be (x^2/2).after that the length and width are decreased by 6 so new length and width are (x-6),(x/2-6) and the difference between these two areas is 108 so we get the equation (x^2/2)-((x-6)*(x^2/2-6))=108.On solving this we get the value of x(length)=16.

Is this solution Helpfull? Yes (15) | No (5)  

Pooja bala singh  (9 years ago)

answer will be 8

Is this solution Helpfull? Yes (10) | No (11)  

Abhinav Satya Kumar  (9 years ago)

answer is :8
{(x*x/2)-(x-6)(x/2-6)}=108
18X+72=108*2
X+4=12
X=8

Is this solution Helpfull? Yes (2) | No (8)  

RASHMI PRIYA  (10 years ago)

l^2-(l-6)^2=108*2 will be the equation.
so the ans will be 21

Is this solution Helpfull? Yes (1) | No (14)  

AADIL HHUSSAIN  (9 years ago)

24
A1-A2=108
L^2/2-(L^2/2-6L-3L+36)=108
3L=108-36
L=72/3=24
L=24 Answer.....

Is this solution Helpfull? Yes (1) | No (9)  

Devesh pandey  (8 years ago)

x^2-18x+72=2a-216
where 2a=x^2
length =16

Is this solution Helpfull? Yes | No   

Prashant Singh  (5 years ago)

l and l/2
a=l^2/2
a'=(l-6)(l/2-6)=(l-6)(l-12)/2=l^2-18l+72/2
a-a'=108
solving this equation,
l=16

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.