Latest Elitmus Aptitude Question SOLUTION: a,b,c in gp and mno in ap value of---(o-n)log a+(o-m)log b+(n-m)log c 1-(o-n)logabc 2--1 3--0

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(#M40058325) ELITMUS Category question logarithm Keep an EYE

a,b,c in gp and mno in ap
value of---(o-n)log a+(o-m)log b+(n-m)log c
1-(o-n)logabc
2--1
3--0

Asked In Elitmus ANANT VIKRAM SINGH (9 years ago)

Unsolved Read Solution (4)

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amit pramanik  (9 years ago)

(o-n)log a + (o-m) log b + (n-m)log c
= o(log a + log b) + n(log c - log a) - m(log b + log c)

since m,n,o in ap, therefore m= 2n - o
o(log a + log b) + n(log c - log a) - (2n- o)(log b + log c)
= olog a + olog b + nlog c - nlog a - 2nlog b - 2nlog c + olog b + olog c
=o[loga +2logb + logc] - n[loga +2logb +logc]
=(o-n)[loga + 2logb + logc
=(o-n) [ loga + 2logb + log(b^2/a)] since a,b,c are in gp, therefore c=b^2/a
=(o-n) [ loga+ 2logb +2logb -log a]
=(o-n) 4logb
=(o-n) log b^4
=(o-n) log b^2 logb^2

=(o-n) logb^2 logac
=(o-n) 2logb logac
=(o-n) 2 logabc

Is this solution Helpfull? Yes (3) | No (2)  

Neeraj Joshi  (9 years ago)

Answer
(o-n)log abc

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nagamani  (9 years ago)

can you explain briefly

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Alok  (8 years ago)

@amit
can u explain which property u applied on second last statement to get answer

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