Latest CTS Aptitude Question SOLUTION: A can swim & cross 50m(the length of swimming pool) in 2 min. B can swim & cross 50m in 2min 15sec. Every time when they meet a bell gong is struck. For 2000m how many bell sounds

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A can swim & cross 50m(the length of swimming pool) in 2 min. B can swim & cross 50m in 2min 15sec. Every time when they meet a bell gong is struck. For 2000m how many bell sounds might be produced?

Asked In CTS (13 years ago)

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OJESH KUMAR MAHULIA  (11 years ago)

answer:41 times

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praneetha  (11 years ago)

A swims 50mts in 2mins*60=120secs;
B swims 50mts in 2.15mins*60=135secs;
To swim 2000mts, 50mts*40times=2000mts;
so A swims for 120secs*40times=4800secs;
so B swims for 135secs*40times=5400secs;
The common factor for 120secs,135secs is 1080secs.
For A, 4800secs/1080secs=4.4(app 4)
For B, 5400secs/1080secs=5
Therefore A and B meet 4 times and hence bell will struck 4
times...........

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anu  (8 years ago)

Please can any body give correct solution

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Arjun Jha  (8 years ago)

Taking LCM of 120 and 135 seconds we get 1080 seconds i.e. 18 minutes; they both meet every 18 minutes.
Now speed of A = 25 m/min and B = 200/9 m/min. A will take 80 minutes to cover 2000 m and B will take 90 minutes for the same.
80 being the smaller value; 4X18 = 72.
Therefore. answer = 4 times.

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