Latest Elitmus Aptitude Question SOLUTION: Set A = { x,11,15,19, 23} *The numbers were randomly distributed in the set. Then find the value of x?? Statement 1: The numbers are in A.P Statement 2: x is a prime number

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(#M40081288) ELITMUS Logical Reasoning question Data Sufficiency Keep an EYE

Set A = { x,11,15,19, 23} *The numbers were randomly distributed in the set. Then find the value of x??

Statement 1: The numbers are in A.P
Statement 2: x is a prime number

Asked In Elitmus Abhishek Saxena (9 years ago)

Unsolved Read Solution (11)

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Read Solution (11) :

Abhishek Saxena  (9 years ago)

@Vivek......Read my statement carefully........Numbers in the Question were randomly arranged like: 19,23,x,11,15
So, if we will use the 1st statement only, value of x can be 7 or 27
But if we will use the 2nd statement along with the first statement, then out of 7 or 27, only 7 is a prime number....So, the required value of x= 7 only......

Now tell guys, am I right??

Is this solution Helpfull? Yes (38) | No (13)  

Vivek shaw  (9 years ago)

Only stmt 1 is sufficient to solve this problem...
23-19=4, 19-15=4. 15-11=4, 11-x=4 ..since numbers are in AP..i.e X=7

Is this solution Helpfull? Yes (9) | No (14)  

eswara reddy  (9 years ago)

with statement 1 the common difference is 4
according to rule of arithmetic progression the number is 7

with statement 2 the prime number has difference 4 with 11 is 7

so answer is
either statement 1 or statement 2 is sufficient for to solve the problem

Is this solution Helpfull? Yes (9) | No (9)  

Abhishek Saxena  (9 years ago)

Both Conditions are required. The value of x is 7.....

Is this solution Helpfull? Yes (7) | No (11)  

rajveer singh  (8 years ago)

If numbers are randomly distributed, then 2 conditions:
a={11,15,,19,23,x} OR
a={x,11,15,19,23}

So both the conditions are required...

Is this solution Helpfull? Yes (6) | No   

Manas Ranjan Satapathy  (9 years ago)

only 1st condition required
as it is in AP its format will be in a,a+d,a+2d ....
here a+d=11
a+2d=15
from solving these both eqn d=4,a=7
so x=7

Is this solution Helpfull? Yes (5) | No (7)  

P.Pandeeswari  (9 years ago)

ans is 7.
each number in a set was increased by 4.
therefore
x+4=11
x=11-4
x=7

Is this solution Helpfull? Yes (3) | No (5)  

shaik sharina  (9 years ago)

7[difference is 4.due to they are in AP]

Is this solution Helpfull? Yes | No   

bondala sravya  (8 years ago)

ans is 7,since given numbers are in A.P the difference between two adjacent no must be constant

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Ashish Kumar Dwivedi  (8 years ago)

Both the conditions are required

Is this solution Helpfull? Yes | No (1)  

sunil  (8 years ago)

only two possible ways to arrange these two numbers in a.p
x,11,15,19,23 or 23,19,15,11,x

from statement one we can say x=7(bcz d=4)
from statement that can be 9,7,5,3,1
so A is answr

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