Latest self Aptitude Question SOLUTION: A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to

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(#M40008433) SELF Numerical Ability question self Keep an EYE

A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?

A. 4 litres, 8 litres B. 6 litres, 6 litres
C. 5 litres, 7 litres D. 7 litres, 5 litres

niru (12 years ago)

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chaitanya  (11 years ago)

Let cost of 1 liter milk be Re 1.
Milk in 1 liter mixture in 1st can = 3/4 lit.
C.P of 1 liter mixture in 1st can =Re 3/4 Milk in 1 liter mixture in 2n d can = 1/2 lit.C.P of 1 liter mixture in 2n d can =Re 1/2Milk in 1 liter final mixture = 5/8 lit.Mean Price = Re 5/8.
C.P of 1 lt mix in 1st Re 3/4 C.P of 1 lt mix in 2nd Re 1/2 Mean Price 5/81/8 1/8
There ratio of two mixtures =1/8 :1/8 = 1:1.So,quantity of mixture taken from each can=1/2*12= 6 liters.

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ashok reddy  (9 years ago)

1st can contain 25%(1/4th) of water and 75%(3/4th) of milk
2nd can contain 50%(1/2) of water and 50%(1/2)of milk
for 12 liters take 1st option 4 liters of 1st can means 3 liters of milk and 1 liter of water
8 liters of 2nd can means 4 liters of milk and 4 liters of water
therefore total of 12 liters (1st option is correct

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