Latest TCS Aptitude Question SOLUTION: A triangle is made from a rope. The sides of the triangle are 25 cm, 11 cm and 31 cm. What will be the area of the square made from the same rope?

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A triangle is made from a rope. The sides of the triangle are 25 cm, 11 cm and 31 cm. What will be the area of the square made from the same rope?

Asked In TCS Akeefar (13 years ago)

Unsolved Read Solution (15)

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Read Solution (15) :

suchandra raavi  (13 years ago)

Since total length of the rope remains constant, both the perimeters of square and triangle are same. Perimeter of triangle=25+11+31=67. Perimeter of square= 4a=67. "a" is the length of the side. So a = 67/4= 16.75. Area =a2= 280.56

Is this solution Helpfull? Yes (48) | No (5)  

maitreyee  (13 years ago)

both the perimeters are same
so perimeter of triangle=25+11+31=67
now for square perimeter is 4*a
so 4a=67, a=16.75
area=a^2=280.5625

Is this solution Helpfull? Yes (18) | No (2)  

sneha chowdary  (13 years ago)

(25+11+31/4)=16.75.
area of square=(16.75)^2=280.56 sq.cm

Is this solution Helpfull? Yes (8) | No (4)  

KALPANA G  (13 years ago)

length of the rope=25+11+31=67cm,
side of the square=67/4=16.75cm,
Area of the square=(side of the square)^2=16.75^2 = 280.5625 cm^2

Is this solution Helpfull? Yes (5) | No   

RAVI  (13 years ago)

yes suchandra raavi is right
area of a triangle=l+b+h

Is this solution Helpfull? Yes (3) | No (9)  

teja  (11 years ago)

length of rope=25+11+31
=67
square has 4 sides.
so each side=67/4
=16.75
area=(16.75)^2
=280.56
ans:280.56

Is this solution Helpfull? Yes (3) | No   

Kapil Agrawal  (13 years ago)

4a=25+11+31
a=67/4
so area = (67/4)^2

Is this solution Helpfull? Yes (2) | No (2)  

Krishna KAnt Tiwari  (13 years ago)

sqr{(25+11+31)/4}

Is this solution Helpfull? Yes (2) | No (1)  

RAVI  (13 years ago)

area of a triangle: L*B*H
then area of a square

Is this solution Helpfull? Yes (1) | No (7)  

Reema khan  (11 years ago)

((25+11+31)/4)^2=280.56

Is this solution Helpfull? Yes (1) | No (1)  

harikrishnan  (10 years ago)

Solution: perimeter of triangle = 25+11+31 = 67
Perimeter of square = 4a =67
Hence a = 67/4 = 16.75
Area of square = a2 = 16.75 * 16.75 = 280.562

Is this solution Helpfull? Yes (1) | No   

Ankit  (9 years ago)

The length of the rope = 11+31+25 = 67 cm
Divide the length by 4 to find the length
of a side of a square made with the rope.
side = 67/4
--
Then area of the square would be (67/4)^2 = 280.56 sq. cm

Is this solution Helpfull? Yes (1) | No (1)  

paramjeet singh  (13 years ago)

p=25+11+31/2=side of square
area=side^2

Is this solution Helpfull? Yes | No (1)  

vin28  (13 years ago)

25+11+31=67
a=67/4
a=16.75
area=a^2=280.5625

Is this solution Helpfull? Yes | No (1)  

Sameer bansod  (10 years ago)

The longest "side" must be the hypotenuse.
So the legs are 25 and 11
---
Area = (1/2)*11*25 = 137.5 sq. cm.
==================================
The length of the rope = 11+31+25 = 67 cm


---
Divide the length by 4 to find the length
of a side of a square made with the rope.
side = 67/4
--
Then area of the square would be (67/4)^2 = 280.56 sq. cm

Is this solution Helpfull? Yes | No   

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