Latest TCS Aptitude Question SOLUTION: One digit is selected from first 30 positive integers , what is the probability that it is divisible by 3 or 5?

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One digit is selected from first 30 positive integers , what is the probability that it is divisible by 3 or 5?

Asked In TCS N.Dayanithi (11 years ago)

Solved krishnamurthy Read Solution (5)

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Read Solution (5) :

asim  (11 years ago)

total no. of events = 30
numbers divisible by 3 are 3,6,9,12,15,18,21,24,27,30 a total no. of 10 numbers
numbers divisible by 5 are 5,10,15,20,25,30 a total no. of 6 numbers
no. of numbers divisible by 3 or 5 are [ (10+6)-2 ] = 14 {since 15,30 comes twice}
HENCE probability is = 14/30 = 0.466667

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krishnamurthy  (11 years ago)

The probability that is divisible by 3 or 5 is 14/30 = 0.4666
Total events=30
feasible events for a number divide by 3=10(3,6,9,12,15,,18,21,24,27,30)
feasible events for a number divide by 5=6(5,10,15,20,25,30)
feasible events for a number divide by 3 and 5=2(15,30)


The probability of number is divide by 3 =14/30
The probability of number is divide by 5 =16/30
The probability of number is divide by 3 and 5 =2/30
so
((10/30)+(6/30)-(2/30))=14/30 =>0.4666

Is this solution Helpfull? Yes (5) | No (1)  

phani  (11 years ago)

14.............p(a or b)=p(a)+p(b)-p(a and b)
p(3)=10
p(5)=6
p(3 and 5)=2
therfore 10+6-2=14..............

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aditya  (11 years ago)

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vvvvvvvvvv  (7 years ago)

no divisible by 3= 30/3=10
no divisible by 5=30/5=6
no divisible by 3 and 5 = 30/15=2
total no divisible by 3 or 5 =10+6-2=13
total no=30
probablity=14/30 = 0.467

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