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A man ate 100 bananas in five days, each day eating 6 more than the previous day. How many bananas did he eat on the first day?
Read Solution (Total 19)
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- let the number of bannanas in first day be x
for consecutive five days it will be like x,x+6,x+12,x+18,x+24
the sum of those are 100, 5x+60=100
so,x=8
ans is 8 - 14 years agoHelpfull: Yes(65) No(0)
- If a is no of bananas eaten on first day, then number of bananas eaten in 5 days = (5/2)*[2*a+ (5-1)*6)= 100
..
so a=8 - 14 years agoHelpfull: Yes(12) No(1)
- first day x
2 day x+6
3 day x+6+6
4 day x+6+6+6
5 day x+6+6+6+6
total,5x+60=100
Ans x=8 - 13 years agoHelpfull: Yes(6) No(1)
- HE'S DONKEY KONG AND HAS LOTSA LIFES
- 12 years agoHelpfull: Yes(4) No(1)
- 1st day- 8
2nd day- 14
3rd day- 20
4th day- 26
5th day- 32
total = 100 - 14 years agoHelpfull: Yes(3) No(6)
- (a)+(a+6)+(a+6+6)+(a+6+6+6)+(a+6+6+6+6)=>5a+60=100
=>5a=40
=>a=8
Finally man first day 8 bananas ate. - 12 years agoHelpfull: Yes(2) No(1)
- 8
- 14 years agoHelpfull: Yes(1) No(4)
- 1st day=8
2nd day=14
3rd day=20
4th day=26
5th day=32 - 14 years agoHelpfull: Yes(1) No(3)
- let he eat x bananas on first day...then
x+(x+6)+(x+12)+(x+18)+(x+24)=100
means
8 bananas.... - 13 years agoHelpfull: Yes(1) No(0)
- 8 banana in first day
- 9 years agoHelpfull: Yes(1) No(0)
- no of bananas in 1st day=> n/2[2a+(n-1)d]=100
here n=5
d=6
a=starting value...
arithmetic progression....
ans=8 - 9 years agoHelpfull: Yes(1) No(0)
- 1 day 6 banana so 5 days 30 banana more eaten total 100-30=70 remain
now 70/5=14 so for single day 14 but already eaten=14-6=8 - 8 years agoHelpfull: Yes(1) No(0)
- ans is 8 .
- 14 years agoHelpfull: Yes(0) No(2)
- total bananas =100
first day =x;
2nd day=x+6;
3rd day =(x+6)+6=x+12;
4th day =(x=12)+6=x+18;
5th day =(x+18)+6=x+24;
number of days sum=5x+60;
so
total bananas 100=5x+60;
x=8;
- 9 years agoHelpfull: Yes(0) No(0)
- let x=no of bananas on first day
x+x+6+x+12+x+18+x+18=100
x=8
ans=8 - 9 years agoHelpfull: Yes(0) No(0)
- total bananas =100
days Bananas
1 x
2 x+6;
3 (x+6)+6=x+12;
4 (x=12)+6=x+18;
5 (x+18)+6=x+24;
number of days
total bananas 100=5x+60;
x=8;
- 9 years agoHelpfull: Yes(0) No(0)
- Ans: Eight
A man ate 100 bananas in five days, each day eating 6 more than the previous day. How many bananas did he eat on the first day - 8 years agoHelpfull: Yes(0) No(0)
- 74
6*4=24 bananas in last 4 days
so remaining on the first day so its 100-24=76 - 7 years agoHelpfull: Yes(0) No(0)
- answer is 8.
it is a simple formation of A.P.
x,x+6,x+12,x+18,x+24 adding all these and equating it to 100 gives the answer 8. - 7 years agoHelpfull: Yes(0) No(0)
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