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A basketball team has 11 players on its roster. Only 5 players can be on the court at one time. How many different groups of 5 players can the team put on the floor?

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The task is only to select a group of 5, not to order them. Hence, this is a combination problem. There are11 players; repetition is not possible among them (one player cannot be counted more than once); and theyare not given the same identity. Hence, there are no indistinguishable objects. Using Formula 3, groups of 5can be chosen from 11 players in 11C5 ways.
12 years agoHelpfull: Yes(8) No(6)

462 combinations.

c(11,5)= 11*10*9*8*7/1*2*3*4*5 = 462
12 years agoHelpfull: Yes(2) No(1)
@Chaitanya,

Definition is correct. But didn't conclude the answer??

Answer is 462 combinations.
12 years agoHelpfull: Yes(1) No(1)
462 combinations.

c(11,2)= 11*10*9*8*7/1*2*3*4*5 = 462
12 years agoHelpfull: Yes(0) No(2)

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