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Maths Puzzle
Find the least n for which the sum of the series 1+2+4+8+ ......... is greater than 10000
Read Solution (Total 4)
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- n=14
(1+2+4+8+16+32+64+128+256+512+1024+2048+4096+ 8192)= (8192+8191) > 10,000 - 12 years agoHelpfull: Yes(3) No(0)
- n=14, the least n for which the sum of the series 1+2+4+8+ ......... is greater than 10000
- 12 years agoHelpfull: Yes(2) No(0)
- n=14.
(1+2+4+8+16+32+64+128+256+512+1024+2028+5056+10112) > 10,000
19243 >10,000
So, n=14 - 12 years agoHelpfull: Yes(2) No(1)
- n=101 is the least n for which the sum of the series 1+2+4+8+ ......... is greater than 10000
- 12 years agoHelpfull: Yes(0) No(3)
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