Find the sum of all two digit numbers which when divided by 4 , yields 1 as remainder.

• (22/2)*(13+97)= 11*110= 1210
• 12 years agoHelpfull: Yes(5) No(3)
• sum of 13+17+...... +97 (22terms)
  
  a=13
  l=97
  n=22
  sum = (n/2)*(a+l)
• 12 years agoHelpfull: Yes(4) No(2)
• 1210
  
  Such numbers are
  13+17+21+25+29+33+37+41+45+49+53+57+61+65+69+73+77+81+85+89+93+97 = 1210
• 12 years agoHelpfull: Yes(3) No(3)
• 9*(11+96) = 9*107= 963
• 12 years agoHelpfull: Yes(1) No(3)