In a class of 12 students , 7 boys and 5 girls.The class has 4 sessions each day,one each of arithmetic ,algebra,geometry and probability.These classes are to be held one after the other in 4 distinct time slots and can be in any sequence .Further there are 2 teachers available and they can teach any topic.
In how many distinct ways can a session be scheduled for two consecutive days if both the teachers have to have equal no. of sessions..?

• When both the teachers have to have equal number of sesions on two consecutive days i.e. we have eight sessions which must be assigned to the two teachers equally i.e. 4 sessions each which can be achieved in C(8, 4) ways. Also the topics can be scheduled in the two days in 4! ways each.
  So the required number of ways are = (4!)^2 x C(8, 4) = 8!
• 12 years agoHelpfull: Yes(3) No(2)