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Maths Puzzle
Compare the numbers 0.99999... (infinitely many 9s) and 1. Which of the following statements is true? Why?
0.99999 ... < 1
0.99999 ... = 1
0.99999 ... > 1
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- well i dont know if this is correct or not, but here is my shot at it.
let 0.999999... = x
multiplying both sides by 10 we get
9.99999.... = 10x
which can again be written as
9 + x = 10x
solving for x we get
x=1.
but by first principle, it is said that
0.99999 is the closest number possible to 1 but not equal to one, because no matter how many 99999 u have, we can still find a number which has a fraction more than it.
0.99999... - 12 years agoHelpfull: Yes(6) No(1)
- I think
0.99999 ... = 1
suppose
0.99999 ... = x
10x= 9.9999999999999
subtracting these eqns
9x= 9.0000000
x=1
so
0.99999 ... = 1 - 12 years agoHelpfull: Yes(2) No(0)
- 0.999999....
- 12 years agoHelpfull: Yes(2) No(1)
- ans o.9999.......... =1. because when ever infinite number is there so it is assume that it is equal to 1.
- 12 years agoHelpfull: Yes(0) No(2)
- statement number 1 is right
0.99999... < 1
because 0.99999... is not complete 1, however when we round off it so it becomes 1 but after all 0.99999... is a part of 1.
- 12 years agoHelpfull: Yes(0) No(1)
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