Compare the numbers 0.99999... (infinitely many 9s) and 1. Which of the following statements is true? Why?

0.99999 ... < 1
0.99999 ... = 1
0.99999 ... > 1

• well i dont know if this is correct or not, but here is my shot at it.
  
  let 0.999999... = x
  multiplying both sides by 10 we get
  
  9.99999.... = 10x
  
  which can again be written as
  
  9 + x = 10x
  
  solving for x we get
  
  x=1.
  
  but by first principle, it is said that
  
  0.99999 is the closest number possible to 1 but not equal to one, because no matter how many 99999 u have, we can still find a number which has a fraction more than it.
  
  0.99999...
• 11 years agoHelpfull: Yes(6) No(1)
• I think
  0.99999 ... = 1
  
  suppose
  0.99999 ... = x
  10x= 9.9999999999999
  subtracting these eqns
  9x= 9.0000000
  x=1
  so
  0.99999 ... = 1
• 11 years agoHelpfull: Yes(2) No(0)
• 0.999999....
• 11 years agoHelpfull: Yes(2) No(1)
• ans o.9999.......... =1. because when ever infinite number is there so it is assume that it is equal to 1.
• 11 years agoHelpfull: Yes(0) No(2)
• statement number 1 is right
  0.99999... < 1
  because 0.99999... is not complete 1, however when we round off it so it becomes 1 but after all 0.99999... is a part of 1.
  
• 11 years agoHelpfull: Yes(0) No(1)