m4maths
Maths Puzzle
Pls check the solution for puzzle
Total no. of words of 5 letters formed by letters of the word BOMBAY.
[You should use only 5 letters out of 6 letters of the word BOMBAY]
solution given is ..................
.....
(1st case all the letters are different
total no. of words of this category = 5*4*3*2*1 = 120
2nd case B comes twice and 3 others
total no. of words of this category = 5*4*3*2*1/2*1 = 60
so total words = 120+60 = 180)
I think answer should be 360
as
solution should be
1st case all the letters are different
total no. of words of this category = 5*4*3*2*1 = 120
2nd case B comes twice and 3 others
total no. of words of this category = 4*(5*4*3*2*1/2*1) = 60*4=240 because there will be 4 combinations of such words.
so total words = 120+240 = 360
pls excuse me if I am wrong.
Read Solution (Total 2)
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- @aman i do think 360 is suitable answer
- 12 years agoHelpfull: Yes(5) No(2)
- well explained , aman.
- 12 years agoHelpfull: Yes(2) No(0)
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