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Maths Puzzle
If a vehicle covers a total distance of 310 Kms in 30 hrs with three different speeds(kmph).If its speed in second part was four less than the twice of the first and in third section exactly double that of first.What was the distances of these three sections(in km),if time taken to cover the different parts are same?
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- let v be the velocity in first part.
now,
10v+(2v-4)*10+(2v)*10=310
v=350/50=7km/hr
velocity of 2nd part=2*7-4=10km/hr
velocity of 3rd part=2*7=14km/hr
so the distances of these three sections(in km) are 70,100&140kms respectively - 12 years agoHelpfull: Yes(2) No(0)
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