When 3/4th of a unit's digit is added to the ten's digit of a two digit number, the sum of the digits becomes 10. If 1/4th of the ten's digit added to the unit digit, then the sum of the digits is 3 less than the sum of the original digits. What is the number ?

• Let the 2digit number be xy.
  
  then 1st statement gives
  (3y/4)+x=10
  => 4x+3y=40
  
  2nd statement gives
  (x/4)+y=(x+y)-3
  => x+4y=4x+4y-12
  => 3x=12
  => x=12
  
  Substituting the value of x in 1st equation, we get
  4(4)+3y=40
  => 16+3y=40
  => 3y=24
  => y=8
  
  Hence the two digit number is 48
• 11 years agoHelpfull: Yes(4) No(0)
• 3/x+4=10;
  x+1/4y=x+y-3
  1/4y=y-3
  y=4
  x=4
  10X+Y=10*4+4=44.
• 11 years agoHelpfull: Yes(0) No(1)