Let exp(m,n)=m to the power n .If exp(10,m)=n*exp(2,2) where m & n are integers then n=.............?
1)25
2)10
3)2
4)5

• option(1) 25 is the answer
  given ,4n=10^m
  
  n=(10^m)/4.
  
  clearly for values of m>1, n is an integer.
  for m=2,we have n=100/4=25
• 12 years agoHelpfull: Yes(7) No(2)
• ans =25
  exp(m,n)=m^n
  exp(10,m)=10^m
  exp(2,2) that means n=2 m=2
  n*exp(2,2)=n*2^2=4n
  now from question exp(10,m)=n*exp(2,2)
  10^2=4n
  n=1004
  n=25.
  
• 12 years agoHelpfull: Yes(7) No(0)
• according to the question,
  
  10 pow m = 4n;
  
  only with n=25 the values can match
  
  10 pow 2 = 4 * 25;
  
  100 = 100
  
  hence n = 25
• 12 years agoHelpfull: Yes(4) No(2)
• 25. exp(10,2)=25*exp(2,2)
• 12 years agoHelpfull: Yes(1) No(0)
• given
  exp(10,m)=4n
  if m=1,
  10=4(2.5),n=2.5
  if m=2
  100=4(25),n=25
  if m=3
  1000=4(250)
  hence it is clear that n is a multiple of 25....
  so ans is n=25
• 12 years agoHelpfull: Yes(1) No(0)