Park, Jack, and Galvin distributed prize money of x dollars among themselves. Park received 3/10 of what Jack and Galvin together received.Jack received 3/11 of what Park and Galvin together received. What is the ratio of the amount received by Park to the amount received by Jack?
(A)7 : 8
(B)8 : 7
(C)10 : 11
(D)14 : 13
(E)77 : 80

• only 2 equations
  P = Park ,J = Jack, G = Galvin;
  P = 3/10(J+G)-----1
  J = 3/11(P+G) ----2
  
  from 1 we can write
  
  G = (10p/3) - J ---3
  
  substitute 3 in 2 making all P and J Terms in the equation.
  
  J = 3/11(P + (10p/3) - J)
  
  solve it
  
  we get P/J = 14/13
  
  thats it!!
• 12 years agoHelpfull: Yes(14) No(1)
• Let the amounts received by Park, Jack and Galvin be
  P,J, and G respectively.
  
  Since the prize money, x was distributed to Park, Jack, and Galvin, the amount that Jack and Galvin together received equals
  x–(the amount received by Park) = 120 –P.
  
  Since we are given that Park received 3/10 of what Jack and Galvin together received,
  we have the equation
  P= (3/10)(x–P)
  
  Solving the equation for P yields
  P= 3x/13
  
  Similarly, since we are given that Jack received 3/11of what Park and Galvin together received (x–J),
  wehave the equation
  J= (3/11)(x–J)
  
  Solving the equation yields
  J= 3x/14
  
  Now
  P:J = 3x/13 : 3x/14 = 14 : 13
  
  The answer is (D).
• 12 years agoHelpfull: Yes(9) No(0)
• According to 1st statement
  Park=1/3(Jack+Galvin)
  => Galvin=3Park-Jack
  
  According to 2nd statement
  Jack=3/11(Park+Galvin)
  => Galvin=(11/3)Jack-Park
  
  
  So we get
  3Park-Jack=(11/3)Jack-Park
  12Park=14Jack
  Park/Jack=7/6
  
  Park:Jack=7:6
• 12 years agoHelpfull: Yes(2) No(9)