exam
Maths Puzzle
Numerical Ability
Permutation and Combination
There ia a question paper consisting of 10 questions. Each question has interval choice of 2 questions. in how many ways can a student attempt one or more question of the given ten question of the paper.
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- Each question can be answered in 3 ways (2 choices + 1 non-attempt). Therefore there are a total of
3^10 ways.
In these 3^10 ways, there is exactly one way in which the student does not attempt any question.
Therefore, required number of ways = (3^10) − 1. - 7 years agoHelpfull: Yes(0) No(0)
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