Q Raju is 10 years elder to Sita 10 years from now Raju would be twice as old as sita

Let the age of Raju be 'x' years and Sita be 'y' years
1st equation will be => x-10=y
2nd equation will be => x+10=2(y-10)
By SOlving two equation Raju age=30 years
Sita Age=20 years
Sita age after 12 years :32 years Ans
12 years agoHelpfull: Yes(31) No(25)
@ARUN,ASHISH PANDEY & RAMYACHITRA :
after solving these 2 equ
i.e. R=S+10 & R+10=2*(S-10)
R=32yrs & S=40yrs
Sita's age after 12yrs will be 40+12= 52yrs
12 years agoHelpfull: Yes(29) No(5)
let raju's age = R, sita's age = S
eq1, R = 10 + S
eq2, R+10 = 2(10 + S - 10) = 2S
thus 2S-10 = 10 + S which gives S =20
thus aftr 12 yrs she will be 20 + 12 = 32 yrs
12 years agoHelpfull: Yes(19) No(18)
let sita age =x
then raju age=x+10
acc to condition raju age+10 (since 10 yrs aftr)=2(sita age bfre 10 yrs )
ie, x+10+10=2(x)
=> x=20
so sita age aftr 12 yrs would be 20+12=32 yrs
12 years agoHelpfull: Yes(14) No(16)
At present, Sita is 40 years old.
After 12 years, Sita will be 52 years old.

If R and S are their present ages, then
R=S+10
and
R+10= 2*(S-10)

solving these eqns, we get
R=50 and S=40

after 12 year sita will be 40+12=52
10 years agoHelpfull: Yes(5) No(3)
raju's present age is 10+x
after 10 years raju's age is 2(x-10)
10+x = 2(10-x)=30 years
after 12 years sita's age is 30+2 = 32 years
10 years agoHelpfull: Yes(4) No(5)
Sita's age=x
so,raju's age =x+10
by given condition,
x+10+10=2(x+10-10)
so x=20
sita's age after 12 yrs=20+12=32yrs
10 years agoHelpfull: Yes(3) No(1)

Q. Raju is 10 years elder to Sita. 10 years from now Raju would be twice as old as sita was before 10 years. How old would be Sita after 12 years.