3,7,12,18,25...........8th Terms

• 8th term=52 ans.
  sol:-
  let x,y & z are the 6th,7th and 8th term.
  then from the series 3,7,12,18,25,x,y,z.
  therefore,
  7-3=4
  12-7=5
  18-12=6
  25-18=7
  x-25=8 -> x=33
  y-33=9 -> y=42
  z-42=10 -> z=52 (8th term).
• 11 years agoHelpfull: Yes(7) No(0)
• 3,7,12,18,25.
  3,7,12,18,25. 33, 42, 52,63
• 11 years agoHelpfull: Yes(2) No(4)
• 8th term = 52
  
  Add 4,5,6,7...... to the previous term.
  
  3+4=7
  7+5=12
  12+6=18
  18+7=25
  25+8=33
  33+9=42
  42+10=52
  
  Final series : 3,7,12,18,25,33,42,52
  
• 11 years agoHelpfull: Yes(1) No(4)
• 3+4=7
  7+5=12
  12+6=18
  18+7=25
  25+8=33
  33+9=42
  42+10=52........
• 11 years agoHelpfull: Yes(1) No(3)