How many methods will be possible for distributing 25 mangoes among 5 persons in such a way that every person would get 3 mangoes compulsorily?

• 15 mangoes are compulsorily given to 5 persons so that each gets 3 mangoes.
  balance 10 mangoes are to be divided among 5 persons .
  
  Number of methods that will be possible for distributing 25 mangoes among 5 persons in such a way that every person would get 3 mangoes compulsorily = (5+10-1)C (10-1) = 14C9 = 14*13*12*11*10/5! = 14*13*11 = 2002 ways
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• In this case, mangoes are assumed to be identical.
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